For the following charge configuration, find the electric field at the point P. q = 8.0 nC, 2 = 12.0 nC, OA=4.0 m and OP=3.0 m. the 2nd charge is at point A. A
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- There can be electrical energy in the absence of electric charge. Both of the first two responses are valid. Neither of the first two responses is valid. O electric fields.We measured equipotentials, which are lines that connect points at which the magnitude of the electric field is equal. Can we tell anything about the direction of electric field lines with these measurements? Propose some additional measurements that would allow us to determine directionality.To move two positive charges closer together, describe the work that must be done. (positive, negative, zero). Describe why you know this must be the case.
- Noneyou have two point charges half a meter apart. the charges have values of positive 1.0 microC and negative 2.0 microC. you want to move the charges apart to twice the distance between them, determine the amount of work needed just need to make sure i understood the question correctly and i followed through with the right method my answer that i got was 18 x 10^-3NThis question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Oppositely charged parallel plates are separated by 4.59 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.83 mm from the positive plate?
- I need help with the first two parts of the question. Thanks!A particle with mass m = 4.50 mg and charge Q = 75.0 μC enters a region of space where there exists an electric field between two vertically arranged parallel conducting plates, which carry opposite charges - these charges establish the field between the plates. The particle enters via a hole in the positively charged plate and after a short time leaves the region via a hole in the negatively charged plate as shown in Figure 2. The field between the plates is 3, 150 ÎN C¹. If the plates are 15.0 cm apart, and the particle enters with a speed of 5.70 x 10²m s¹, determine the speed of the particle as it exits the region between the plates. V Figure 2:using no mathematics, explain the physical mechanism by which bound surface charge arises in a dielectric material in an external electric field – how does it come about, what does it ‘look’ like?