There is a uniform electric field, directed toward the right. If an externl force pushes a positive charged particle to the left, what will happen to the electric potential energy of the system?
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There is a uniform electric field, directed toward the right. If an externl force pushes a positive charged particle to the left, what will happen to the electric potential energy of the system?
Given,
An electric field in the right direction and moving a positive charge in left direction
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Solved in 3 steps
- Problem 18.17 - Enhanced - with Solution You may want to review (Page). For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Parallel plates and conservation of energy. Part A An electron is to be accelerated from a velocity of 3.50x 10 m/s to a velocity of 7.50x105 m/s. Through what potential difference must the electron pass to accomplish this? for Panze for Partido for Part redo foart A refor Part A keyboard shortcuts for Part A help for Part. A Viniital - Viinal= Submit Part B Request Answer Through what potential difference must the electron pass if it is to be slowed from 7.50x105 m/s to a halt? Vinitial - Vinal= Submit for Partfondo for Part redo folet B reor Part B keyboard shortcuts for Part B help for Part B Request Answer VOn planet Tehar, the free-fall acceleration is the same as that on Earth, but there is also a strong downward electric field that is uniform close to the planet's surface. A 1.98-kg ball having a charge of 5.22 ?C is thrown upward at a speed of 20.1 m/s. It hits the ground after an interval of 4.10 s. What is the potential difference between the starting point and the top point of the trajectory? (Use 9.8 m/s2 for the acceleration due to gravity.)1.0 nC + 3.0 cm / \ 3.0 cm 3.0 cm -2.0 nC -2.0 nC Oh no! That triangle is back! Except this time Prof. P was tired of that wonky 1.0 nC positive charge and replaced it with a new exciting and debonair positive 0.2 nC charge (those two boring negative charges and all the distances stayed the same). What is the electric potential energy of this too- exciting for the world arrangement of charges now (in milliJoules)?
- A proton enters a parallel plate system moving with an initial velocity of 9413.1 m/s perpendicular to the electric field. The proton enters at the the positive plate and the electric field between the plates moves it in the direction of the negative plate. The plate separation distance is 19.2 cm and the potential difference between the plates is 1.9 V. What is the magnitude of the final velocity of the proton when it hits the negative plate? ( Please state what kinematics formula was used to find final velocity through the steps.)A proton (mass = 1.67 × 10-27 kg, charge = 1.60 × 10-19 C) moves from point A to point B under the influence of an electrostatic force only. At point A the proton moves with a speed of 50 km/s. At point B the speed of the proton is 92.9 km/s. Determine the potential difference VB -VA (in units of А volts). Select one: O A. 24.02 О в. 31.38 Ос. -50.38 O D. -31.99 O E. 2.12Answer must be in standard form scientific notation with SI units that do not have prefixes except for kg. Provide the answer with the correct amount of significant figures. Thank you so much I greatly appreciate it
- 19.1.1. Two electrons are separated by a distance R. If the distance between the charges is increased to 2R, what happens to the total electric potential energy of the system? a) The total electric potential energy of the system would increase to four times its initial value. b) The total electric potential energy of the system would increase to two times its initial value. c) The total electric potential energy of the system would remain the same. d) The total electric potential energy of the system would decrease to one half its initial value. e) The total electric potential energy of the system would decrease to one fourth its initial value.Answer option D only. I will rate accordingly.An equilateral triangle with a side of length a has point electric charges q , 2q and 3q, respectively, at its vertices. Calculate the electric field and electric potential at the center of the equilateral triangle in terms of Coulomb's constants, a and q.