kg. It moves from A small particle has charge -6.60 μC and mass 2.50x10 point A, where the electric potential is V₁ = 220 V, to point B, where the

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Chapter1: Units, Trigonometry. And Vectors
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Problem 18.18
A small particle has charge -6.60 μC and mass 2.50x104 kg. It moves from
point A, where the electric potential is V₁ = 220 V, to point B, where the
electric potential V₂ = 620 V. The electric force is the only force acting on the
particle. The particle has a speed of 5.00 m/s at point A.
Part A
What is its speed at point B?
Express your answer in meters per second to three significant figures.
ID] ΑΣΦ
Submit
Part B
Is it moving faster or slower at B than at A?
Faster
Slower
Request Answer
Submit
Request Answer
?
m/s
Transcribed Image Text:Problem 18.18 A small particle has charge -6.60 μC and mass 2.50x104 kg. It moves from point A, where the electric potential is V₁ = 220 V, to point B, where the electric potential V₂ = 620 V. The electric force is the only force acting on the particle. The particle has a speed of 5.00 m/s at point A. Part A What is its speed at point B? Express your answer in meters per second to three significant figures. ID] ΑΣΦ Submit Part B Is it moving faster or slower at B than at A? Faster Slower Request Answer Submit Request Answer ? m/s
Problem 18.17 - Enhanced - with Solution
You may want to review (Page).
For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Parallel plates and conservation of energy.
Part A
An electron is to be accelerated from a velocity of 3.50x108 m/s to a velocity of 7.50x10 m/s. Through what potential difference must the electron pass to accomplish this?
Vinitial - Vfinal =
Submit
Part B
ΕΠΙΑΣΦ
Request Answer
Vinitial - Viinal
Submit
Through what potential difference must the electron pass if it is to be slowed from 7.50x108 m/s to a halt?
Request Answer
?
ΑΣΦ
V
?
V
Transcribed Image Text:Problem 18.17 - Enhanced - with Solution You may want to review (Page). For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Parallel plates and conservation of energy. Part A An electron is to be accelerated from a velocity of 3.50x108 m/s to a velocity of 7.50x10 m/s. Through what potential difference must the electron pass to accomplish this? Vinitial - Vfinal = Submit Part B ΕΠΙΑΣΦ Request Answer Vinitial - Viinal Submit Through what potential difference must the electron pass if it is to be slowed from 7.50x108 m/s to a halt? Request Answer ? ΑΣΦ V ? V
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