For the fluorescence signal from solutions stored under different conditions. From last lecture, which means differ significantly? Treatment/ Group Conditions Replicate Mean A 102 100 101 101 A: Freshly prepared B 101 101 104 102 B: Stored for 1 hr in the dark C: Stored for 1 hr in subdued light D: Stored for 1 hr in bright light 99 97 94 92 Overall mean 98 Anova: Single Factor SUMMARY Groups Count Sum Average Va riance 3 303 101 1 Decision: Since calculated F(20.67) is more than critical F of 4.07 (or since p-value is 0.0004 which is smaller than a =0.05), we reject the null hypothesis. 3 306 102 3 3 291 97 4 3 276 92 4 ANOVA e of Vario df MS F P-value F crit Conclusion: The sample means do differ significantly. Between C 186 3 62 20.66667 0.0004 4.066181 Within Grd 24 8 3 Total 210 11

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question

Anova exercise . Show the step and output using Excel.

= Menu v
Home
Insert
Page Layout
Formulas
Review
View
Tools
Q Click to find commands
Data
X Cut
- A A
Calibri
11
General
.00
Paste L copy - Format
BIU- - E -
Merge and
Wrap
AutoSum AutoFilter Sort Format
Conditional
Format as
Painter
Center
Тext
Formatting
Table
P25
® fx
A
В
E
F
G
H
M
N
1
C =
E;ni
Replicate 1 Replicate 2 Replicate 3 Mean
TSS = Eau (Xij – x)² = Eau *ij – C
(E, xij²)
E" n;(X; – x)² = E;
A
102
100
101
101
-
5 В
101
101
104
102
6 с
97
95
99
97
SSB =
- C
nį
7 D
90
92
94
92
SSW = TSS – SSB
df within = df total – df between
Where
.2
X: Overall mean
X;: Mean of group/treatment i
4
Xij: data for treatment i and replicate j
_6
n¡: no of replicates in treatment i
_8
In this eg., i=4 and j=n
20
21
2
Transcribed Image Text:= Menu v Home Insert Page Layout Formulas Review View Tools Q Click to find commands Data X Cut - A A Calibri 11 General .00 Paste L copy - Format BIU- - E - Merge and Wrap AutoSum AutoFilter Sort Format Conditional Format as Painter Center Тext Formatting Table P25 ® fx A В E F G H M N 1 C = E;ni Replicate 1 Replicate 2 Replicate 3 Mean TSS = Eau (Xij – x)² = Eau *ij – C (E, xij²) E" n;(X; – x)² = E; A 102 100 101 101 - 5 В 101 101 104 102 6 с 97 95 99 97 SSB = - C nį 7 D 90 92 94 92 SSW = TSS – SSB df within = df total – df between Where .2 X: Overall mean X;: Mean of group/treatment i 4 Xij: data for treatment i and replicate j _6 n¡: no of replicates in treatment i _8 In this eg., i=4 and j=n 20 21 2
• For the fluorescence signal from solutions stored under different
conditions. From last lecture, which means differ significantly?
Treatment/
Group
Conditions
Replicate
Mean
A
102
100
101
101
A: Freshly prepared
B
101
101
104
102
B: Stored for 1 hr in the dark
C: Stored for 1 hr in subdued light
D: Stored for 1 hr in bright light
97
95
99
97
D
90
92
94
92
Overall mean
98
Anova: Single Factor
SUMMARY
Groups
Count
Sum
Averoge
Voriance
3
303
101
1
Decision: Since calculated F(20.67) is more than critical F
of 4.07 (or since p-value is 0.0004 which is smaller than a
=0.05), we reject the null hypothesis.
B
3
306
102
3
3
291
97
4
D
3
276
92
4
ANOVA
ce of Vario
df
MS
F
P-value
F crit
Conclusion: The sample means do differ significantly.
Between C
186
3
62 20.66667
0.0004 4.066181
Within Gro
24
8
Total
210
11
Transcribed Image Text:• For the fluorescence signal from solutions stored under different conditions. From last lecture, which means differ significantly? Treatment/ Group Conditions Replicate Mean A 102 100 101 101 A: Freshly prepared B 101 101 104 102 B: Stored for 1 hr in the dark C: Stored for 1 hr in subdued light D: Stored for 1 hr in bright light 97 95 99 97 D 90 92 94 92 Overall mean 98 Anova: Single Factor SUMMARY Groups Count Sum Averoge Voriance 3 303 101 1 Decision: Since calculated F(20.67) is more than critical F of 4.07 (or since p-value is 0.0004 which is smaller than a =0.05), we reject the null hypothesis. B 3 306 102 3 3 291 97 4 D 3 276 92 4 ANOVA ce of Vario df MS F P-value F crit Conclusion: The sample means do differ significantly. Between C 186 3 62 20.66667 0.0004 4.066181 Within Gro 24 8 Total 210 11
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Research Ethics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman