For the dehydrohalogenation (E2) reaction shown, draw the Zaitsev product(s) resulting from elimination involving C3-C4 (i.c., the carbon atoms depicted with stereobonds). Show the product stereochemistry clearly. If there is more than one organic product, both products may be drawn in the same box. Ignore elimination involving C3 and any carbon atom other than C4. Br H KOH EtOH Heat L

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For the dehydrohalogenation (E2) reaction shown, draw the Zaitsev product(s) resulting from elimination involving C3–C4 (i.e., the carbon atoms depicted with stereobonds). Show the product stereochemistry clearly. If there is more than one organic product, both products may be drawn in the same box. Ignore elimination involving C3 and any carbon atom other than C4.

**Chemical Reaction Diagram Explanation**

- **Reactant Structure**: The structure shown on the left is a haloalkane with a bromine (Br) atom attached to a saturated carbon chain. The molecule is depicted using stereobonds to indicate the 3D arrangement: two hydrogens (H) are shown branching off the chain.
  
- **Reagents and Conditions**: The reaction uses potassium hydroxide (KOH) and ethanol (EtOH) with heat as the reagents and reaction conditions, which facilitate the elimination process.

- **Product Structure**: The product on the right side of the arrow is an alkene, which reflects the elimination of a hydrogen bromide (HBr) molecule. The diagram illustrates the formation of a double bond between the two carbon atoms, previously connected. The stereochemistry is shown, with hydrogens explicitly drawn to indicate their spatial orientation. The resulting structure depicts a more substituted, stable alkene consistent with Zaitsev’s rule, where the double bond forms between the most substituted carbon atoms. 

This content guides learners through understanding the E2 reaction mechanism, the concept of Zaitsev's rule, and visualizing stereochemistry in organic reactions.
Transcribed Image Text:**Text Transcription for Educational Website** For the dehydrohalogenation (E2) reaction shown, draw the Zaitsev product(s) resulting from elimination involving C3–C4 (i.e., the carbon atoms depicted with stereobonds). Show the product stereochemistry clearly. If there is more than one organic product, both products may be drawn in the same box. Ignore elimination involving C3 and any carbon atom other than C4. **Chemical Reaction Diagram Explanation** - **Reactant Structure**: The structure shown on the left is a haloalkane with a bromine (Br) atom attached to a saturated carbon chain. The molecule is depicted using stereobonds to indicate the 3D arrangement: two hydrogens (H) are shown branching off the chain. - **Reagents and Conditions**: The reaction uses potassium hydroxide (KOH) and ethanol (EtOH) with heat as the reagents and reaction conditions, which facilitate the elimination process. - **Product Structure**: The product on the right side of the arrow is an alkene, which reflects the elimination of a hydrogen bromide (HBr) molecule. The diagram illustrates the formation of a double bond between the two carbon atoms, previously connected. The stereochemistry is shown, with hydrogens explicitly drawn to indicate their spatial orientation. The resulting structure depicts a more substituted, stable alkene consistent with Zaitsev’s rule, where the double bond forms between the most substituted carbon atoms. This content guides learners through understanding the E2 reaction mechanism, the concept of Zaitsev's rule, and visualizing stereochemistry in organic reactions.
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