Draw the major organic product of the reaction shown. If stereochemistry is present, clearly show stereochemistry by drawing two in-plane, one wedged and one dashed bond. Br H CH3OH

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**Reaction Analysis and Product Drawing with Stereochemistry**

**Task:**

Draw the major organic product of the reaction shown. If stereochemistry is present, clearly show stereochemistry by drawing two in-plane, one wedged, and one dashed bond.

**Reactants and Conditions:**

- The starting compound is a bromocyclohexane derivative with a wedged bromine (Br) and a dashed hydrogen (H) indicating stereochemistry. The Br and H are on adjacent carbon atoms.
- The reaction involves methanol (CH₃OH) as a reagent.

**Instructions:**

1. **Identify the Stereochemical Center:**
   - The starting molecule contains a stereocenter where Br and H are positioned on adjacent carbons with opposite stereochemistry (one wedged, one dashed).

2. **Reaction Type:**
   - Likely involves an S<sub>N</sub>1 reaction mechanism where the bromine leaves, forming a carbocation intermediate.

3. **Drawing the Product:**
   - Replace the bromine with a methoxy group (OCH₃) from methanol.
   - Retain the stereochemistry at the original carbon that was bonded to bromine.

4. **Stereochemistry Display:**
   - Draw the methoxy group with stereochemistry, showing:
     - Two in-plane bonds for two substituents.
     - A wedge for the group coming out of the plane.
     - A dash for the group going into the plane.

This task helps in understanding reaction mechanisms and the importance of stereochemistry in organic synthesis.
Transcribed Image Text:**Reaction Analysis and Product Drawing with Stereochemistry** **Task:** Draw the major organic product of the reaction shown. If stereochemistry is present, clearly show stereochemistry by drawing two in-plane, one wedged, and one dashed bond. **Reactants and Conditions:** - The starting compound is a bromocyclohexane derivative with a wedged bromine (Br) and a dashed hydrogen (H) indicating stereochemistry. The Br and H are on adjacent carbon atoms. - The reaction involves methanol (CH₃OH) as a reagent. **Instructions:** 1. **Identify the Stereochemical Center:** - The starting molecule contains a stereocenter where Br and H are positioned on adjacent carbons with opposite stereochemistry (one wedged, one dashed). 2. **Reaction Type:** - Likely involves an S<sub>N</sub>1 reaction mechanism where the bromine leaves, forming a carbocation intermediate. 3. **Drawing the Product:** - Replace the bromine with a methoxy group (OCH₃) from methanol. - Retain the stereochemistry at the original carbon that was bonded to bromine. 4. **Stereochemistry Display:** - Draw the methoxy group with stereochemistry, showing: - Two in-plane bonds for two substituents. - A wedge for the group coming out of the plane. - A dash for the group going into the plane. This task helps in understanding reaction mechanisms and the importance of stereochemistry in organic synthesis.
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