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Give detailed mechanism Solution with explanation needed don't give Ai generated solution avoid handwritten Solution
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- 3) Draw the structures of the major organic product(s) for the following reactions. HI in CH₂Cl₂ 3 excess Cl₂ in H₂O H₂SO4 in H₂O (Two products) Br-Cl in THF 1) BH3 2) alkaline H₂O₂ OSO4 + HOOHDraw the structure of the major organic product of the reaction. O CH3 CI 1. LiAlH4, ether 2. H₂0* • You do not have to consider stereochemistry.All I need help with, is everything about this process, please send help!
- Classify the reaction below as an oxidation, a reduction, or neither. Br2 CH2Cl2 Br "Br2. The following carbocation is generated as an intermediate in the addition of H-Br to an alkene. Draw the structure of all possible alkenes that could have formed this intermediate.Q7: For the following reactions, indicate the reaction conditions that would provide the indicated product in a high yield. Note the major reaction pathway that would take place (SN1, SN2, E1, or E2) Note: There may be other products that are not shown. There maybe more than one plausible pathway. Br H3C OH H3C CI ... H3C SCH2CH3 CI i SCH2CH3 ཨ་ Br System Sett
- The reaction in the box is missing a reagent/reactant... NCH3 NHCH3 Which of the following would you use to convert the starting material into the product in high yield? A) An oxidation reagent such as H2CrO4 B) A base such as NaOH/H20 C) An acid such as H2SO4 D) A reduction agent such as NABH4 A В C O DProvide a mechanism for the following reaction. Use curved arrows to depict electron flow. OCH, OHC CH₂OH H₂SO4 CO,CH,Classify the reaction below as an oxidation, a reduction, or neither.(CH3)2CHCH2OH → (CH3)2CHCHOA) oxidationB) reductionC) neither
- Draw the major organic product for the reaction conditions shown. CH3 mCPBA CF3SO3H CH₂Cl₂CH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:please answer both questions