For the current mirror circuit shown below, we have = 100 for both Q1 and Q2. When IREF = 1mA and Vo = 5V, the mirror current Io =IREFQ₁+VBEHll₂Vo_mA. Consider the oscillator circuit shown below where a limiter is inserted in the feedback loop for amplitude control. If we want the output voltage to have the amplitude of 5V, then1₂the ratio of the two resistances910.7× = 0.9 VАА"₁C=wwwR-0%10.9 (1+2) VoVoltÄÄiD₁ D₂===+0.7 VVr-0.7 VAF

For the given current mirror circuit the value of the output current Io needs to be calculated based…

Answered: For the current mirror circuit shown…

For the current mirror circuit shown below, we have = 100 for both Q1 and Q2. When IREF = 1mA and Vo = 5V, the mirror current lo _mA.

Introductory Circuit Analysis (13th Edition)

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ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

For the current mirror circuit shown below, we have = 100 for both Q1 and Q2. When IREF = 1mA and Vo = 5V, the mirror current Io =
IREF
Q₁
+
VBE
Hl
l₂
Vo
_mA.

Consider the oscillator circuit shown below where a limiter is inserted in the feedback loop for amplitude control. If we want the output voltage to have the amplitude of 5V, then
1₂
the ratio of the two resistances
91
0.7× = 0.9 V
АА
"₁
C=
www
R
-0%
10.9 (1+2) Vo
Volt
ÄÄ
i
D₁ D₂
===
+0.7 V
Vr
-0.7 V
AF

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