Calculate the current for the JFET for VGS = −2 V and VDS = 0.5 V.(b) Repeat for VGS = −1 V and VDS = 6 V 1.501.00Ipss0.500-0.500-6 -5 -4 –3 -2 -1 0 I 2 3Gate-source voltage (V)Figure 4.35 Transfer characteristic for a JFET operating in pinch-Drain-source current (uA)

Answered: 1.50 1.00 Ipss 0.500 -0.500 -6 -5 -4 –3…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

Calculate the current for the JFET for V_GS = −2 V and V_DS = 0.5 V.
(b) Repeat for V_GS = −1 V and V_DS = 6 V

1.50
1.00
Ipss
0.500
-0.500
-6 -5 -4 –3 -2 -1 0 I 2 3
Gate-source voltage (V)
Figure 4.35 Transfer characteristic for a JFET operating in pinch-
Drain-source current (uA)

Expert Solution

Step 1

a) For finding the region of operation of transistor, we calculate difference of gate to source voltage and pinch off voltage.

$= V_{G S} - V_{P} = - 2 V - (- 4 V) = + 2 V$

Here, positive value shows that transistor is operating in triode region.

Step 2

Calculating drain current by the below expression

$I_{D} = \frac{2 I_{D S S}}{{V_{P}}^{2}} (V_{G S} - V_{P} - \frac{V_{D S}}{2}) V_{D S} I_{D} = \frac{2 (0.2 m A)}{{(- 4)}^{2}} (- 2 V - 4 V - \frac{0.5 V}{2}) 0.5 V I_{D} = \frac{(0.4 m A)}{16} \times 1.75 \times 0.5 I_{D} = 21.9 μ A$

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