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Computer Engineering
For the code shown below, construct the following: a) The basic blocks of instructions and the control-flow graph (CFG). b) The live variables at the end of each basic block. You do not need to determine the live variables before and after each basic block and justify your answer for the value presented for the basic block containing instructions at line 6 and 7. a = 1 b = 2 L0: c = a + b d = c - a if c < d goto L2 L1: d = b + d if d < 1 goto

For the code shown below, construct the following: a) The basic blocks of instructions and the control-flow graph (CFG). b) The live variables at the end of each basic block. You do not need to determine the live variables before and after each basic block and justify your answer for the value presented for the basic block containing instructions at line 6 and 7. a = 1 b = 2 L0: c = a + b d = c - a if c < d goto L2 L1: d = b + d if d < 1 goto

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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For the code shown below, construct the following:

a) The basic blocks of instructions and the control-flow graph (CFG).

b) The live variables at the end of each basic block. You do not need to determine the live variables before and after each basic block and justify your answer for the value presented for the basic block containing instructions at line 6 and 7.

  1. a = 1
  2. b = 2
  3. L0: c = a + b
  4. d = c - a
  5. if c < d goto L2
  6. L1: d = b + d
  7. if d < 1 goto L3
  8. L2: b = a + b
  9. e = c – a
  10. if e == 0 goto L0
  11. a = b + d
  12. b = a – d
  13. goto L4
  14. L3: d = a + b
  15. e = e + 1
  16. goto L1
  17. L4: return
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