For the circuit shown below (B1 150), détermine: - 1. the de values (Va1, V82, Vc1. Vcz, VE1, VE2, VCE1, VCE2).
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- Known Vsat for LM741 ± 14V for source voltage Vs ± 15V. If Vi1 = 3 V and Vi2 = 4 V, Ri1 = Ri2 = Ro2 = 1 K Ohms. Define what is the value of Vo? how muchCalculate the output for the given circuit. R2 R2 Voo ww R1 Let the values are R1=250.6ohm,R2%=978.86 ohm .The error voltage is =74 Volt and he initial value of output is 4.9 Volt. Vout = volt.Q2: A PMMC(Galvanometer instrument) has a resistance of 10052 and FSD for a current of 400Au. A shunt arrangement is shown in order to have an multi-range ammeters(AYRTON). Determine the various ranges to which the ammeter may be switch. Assume the R1-R2-R3-R4-0.00152. PMMC 10052
- How you have find the value of k, Pls expalin in detailthis question is related to subject ELECTRONICS DEVICES AND CIRCUITS . solve this question on A4 page manually with step by step clearly. kindly send with in 30 mintues. thanks.Calculate the output for the given circuit . R2 R2 Voo R R R1 ww Let the values are R1=257.6ohm,R2=828.97 ohm .The error voltage is =8.9 Volt and the initial value of output is 2 Volt. Vout = volt.
- What is an SF6 circuit breaker? Write down the construction and working of and SF6 circuit breaker. Please don't write on paperHi, please show your complete and correct, solution and answer to this circuit problem. This is all about Diode Clipper and Clamper. Please show the full details of your work. Thanks! ASAP!5a. What is E2=? 5b. What is E3=? 5c. What is the potential difference of b relative to point a (V_ba)?
- use the constant voltage drop model in analyzing the diode circuit below: 10 92 V₁ (+ M 1 V D₁ If V₁ is -3 V, what would be the state of the diodes? A. D₁ and D₂ are both OFF C B. D₁ is OFF and D₂ is ON - 1 V D₂ C. D₁ is ON and D₂ is OFF D. D₁ and D₂ are both ON + 1092 VoA charging circuit that will deliver constant DC current will be designed. The input of the circuit is 220V / 50Hz AC and its outputIt will be 5V / 2A DC.The circuit will consist of 3 parts:AC transformer will reduce the voltage on the inputii. AC rectifier circuit will convert low AC voltage to DCiii. Current source, this part will keep the current at the output constant.You determine the transformer drop rate in the first part. Its output is low voltage ACas the source and design the second and third parts accordingly.Consider a PV Module with 4 solar PV cells with the Size of each 10cm x 10cm are connected in Parallel. Choose the correct statement for the above PV Module. (Assume necessary data) a. The output voltage is 0.5 V, the output power is 12W b. The output voltage is 2 V, the output power is 12W c. The output voltage is 12 V, the output power is 6W d. The output voltage is 0.5 V, the output power is 6W