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25V ° D) shetch the wave forms of Vc and ic VE (V) 0.446 of €15.6ms. [25(1-e V] 1 5t=28mA ic (mA →t -4/5.6ms 0.446e mA] 50=28mA For the circuit in Figure, composed of standard values: C R 8 +15 V (t = 0 s) 1 56 ΚΩ Lic + 0.1 µF vc -10 V Figure 1:

25V ° D) shetch the wave forms of Vc and ic VE (V) 0.446 of €15.6ms. [25(1-e V] 1 5t=28mA ic (mA →t -4/5.6ms 0.446e mA] 50=28mA For the circuit in Figure, composed of standard values: C R 8 +15 V (t = 0 s) 1 56 ΚΩ Lic + 0.1 µF vc -10 V Figure 1:

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can you check if my answers are correct

(a) Determine the time constant of the circuit.

T = 5.6ms


(b) Write the mathematical equation for the voltage vC following the closing
of the switch.

Vc = 25(1 - e-t/5.6ms)V

(c) Write the mathematical expression for the current iC following the closing of the switch.

This one was tricky since I guess that 25V is considered E voltage. so I thought this would be divided by the resistor which I got Ic = 0.446e-t/5.6ms


(d) Sketch the waveforms of vC and iC

 

25V ° D) shetch the wave forms of Vc and ic VE (V) 0.446 of €15.6ms. [25(1-e V] 1 5t=28mA ic (mA →t -4/5.6ms 0.446e mA] 50=28mA
Transcribed Image Text:25V ° D) shetch the wave forms of Vc and ic VE (V) 0.446 of €15.6ms. [25(1-e V] 1 5t=28mA ic (mA →t -4/5.6ms 0.446e mA] 50=28mA
For the circuit in Figure, composed of standard values: C R 8 +15 V (t = 0 s) 1 56 ΚΩ Lic + 0.1 µF vc -10 V Figure 1:
Transcribed Image Text:For the circuit in Figure, composed of standard values: C R 8 +15 V (t = 0 s) 1 56 ΚΩ Lic + 0.1 µF vc -10 V Figure 1:
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