For the circuit below, derive the Thévenin equivalent impedance operator Zeg of the deactivated network looking into the terminals a and b. Write Zeg that the coefficient in front of the p² term in the denominator is unity. Note that Zeg = v,/i, with v, = 0 and i, = 0, but it can be found here by combin- ing impedances in series and parallel. so Find the open-circuit output voltage voc = v; with i, = 0. ос is a ee 2p 2Ω 4 v,(t) eq
For the circuit below, derive the Thévenin equivalent impedance operator Zeg of the deactivated network looking into the terminals a and b. Write Zeg that the coefficient in front of the p² term in the denominator is unity. Note that Zeg = v,/i, with v, = 0 and i, = 0, but it can be found here by combin- ing impedances in series and parallel. so Find the open-circuit output voltage voc = v; with i, = 0. ос is a ee 2p 2Ω 4 v,(t) eq
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.61P
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![For the circuit below, derive the Thévenin equivalent impedance operator Ze
of the deactivated network looking into the terminals a and b. Write Zeg so
that the coefficient in front of the p² term in the denominator is unity. Note
that Zeg = v,/i, with v, = 0 and i, = 0, but it can be found here by combin-
ing impedances in series and parallel.
eq
v; with i, = 0.
Find the open-circuit output voltage voc
i,
a
2p
2Ω
4
- Zeg
v,(t)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb961d4e0-2d0c-49bd-b28e-63daa8f1cede%2Fe136c115-4e8c-4bc6-bf89-3f99c95c4204%2Fg159gub_processed.png&w=3840&q=75)
Transcribed Image Text:For the circuit below, derive the Thévenin equivalent impedance operator Ze
of the deactivated network looking into the terminals a and b. Write Zeg so
that the coefficient in front of the p² term in the denominator is unity. Note
that Zeg = v,/i, with v, = 0 and i, = 0, but it can be found here by combin-
ing impedances in series and parallel.
eq
v; with i, = 0.
Find the open-circuit output voltage voc
i,
a
2p
2Ω
4
- Zeg
v,(t)
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