For the BJT amplifier circuit of Fig. 14-9, determine the lower- and higher-cutoff frequencies. C-18pF Cbe = 24pF Cw₂ = 8pF C=12pF Cw=10pF Cs Сс B=80 10μF 10F R$≤0.1k R1.20 R$ 3.3K R₁4.7k VEE 4V Vcc 16V Fig. 14-9

University Physics Volume 2
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Chapter15: Alternating-current Circuits
Section: Chapter Questions
Problem 54AP: What is the impedance of an RLC series circuit at the resonant frequency?
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For the BJT amplifier circuit of Fig. 14-9, determine the lower- and higher-cutoff
frequencies.
C-18pF
Cbe = 24pF
Cw₂ = 8pF
C=12pF
Cw=10pF
Cs
Сс
B=80
10μF
10F
R$≤0.1k
R1.20
R$ 3.3K
R₁4.7k
VEE 4V
Vcc
16V
Fig. 14-9
Transcribed Image Text:For the BJT amplifier circuit of Fig. 14-9, determine the lower- and higher-cutoff frequencies. C-18pF Cbe = 24pF Cw₂ = 8pF C=12pF Cw=10pF Cs Сс B=80 10μF 10F R$≤0.1k R1.20 R$ 3.3K R₁4.7k VEE 4V Vcc 16V Fig. 14-9
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