For the below structure a moment is applied at E, find the equilibrium moments exerted bythe members on the joint (EI is constant)4 m1000 kN.mE5m6 m3 m(A) M 23 = 275 kN m, MD =366 kN m, M, =129 kN - m, M-c = 237 kN · m(B) M =275 kN m, M = 363 kN m, MEc(C) M 2 = 275 kN m, M=363 kN m, M = 220 kN · m, M- =137 kN · m(D) M = 275 kN m, MED = 366 kN m, M = 220 kN m, Mc =137 kN m%3D%3DEB%3DEAEC220 kN m, MED =137 kN m%3D%3D%3D%3DED%3DEAEB%3D%3DEC%3DAnswerAВCRED Dhp40 F6FSF7F8F9

Answered: Image /qna-images/answer/5625072b-ea1d-41d2-8f9b-fb3d1b7bfaaa.jpg

For the below structure a moment is applied at E, find the equilibrium moments exerted by the members on the joint (EI is constant) B 4 m 1000 kN.m E 5 m 6 m 3 m (A) M = 275 kN m, MED = 366 kN.m, ME =129 kN m, Mgc (B) MEA =275 kN m, M =363 kN m, Mgc (C) Mc =275 kN m, ME =363 kN m, M (D) M E = 275 kN m, MED = 366 kN m, M = 220 kN m, Mgc =137 kN m 237 kN m = 220 kN · m, M ED =137 kN m 220 kN m, MED =137 kN m %3D %3D %3D %3D %3D %3D Answer A

For the below structure a moment is applied at E, find the equilibrium moments exerted by the members on the joint (EI is constant) B 4 m 1000 kN.m E 5 m 6 m 3 m (A) M = 275 kN m, MED = 366 kN.m, ME =129 kN m, Mgc (B) MEA =275 kN m, M =363 kN m, Mgc (C) Mc =275 kN m, ME =363 kN m, M (D) M E = 275 kN m, MED = 366 kN m, M = 220 kN m, Mgc =137 kN m 237 kN m = 220 kN · m, M ED =137 kN m 220 kN m, MED =137 kN m %3D %3D %3D %3D %3D %3D Answer A

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

r the below structure a moment is applied at E, find the equilibrium moments exerted by e members on the joint (EI is constant) 4 m 1000 kN.m 五 E 5 m 6 m 3 m (A) M =3 = 275 kN-m, ME = 366 kN·m, M2 =120 kN·m, Mgc = 237 kN -m (B) M =275 kN•m, M = 363 kN m, MEc = 220 kN · m, M D =137 kN m (C) M gc = 275 kN•m, M¤ = 363 kN m, M = = 220 kN - m, M =, =137 kN -m (D) M R = 275 kN · m, M gn = 366 kN·m, M-, = 220 kN · m, M-c =137 kN •m %3D %3D %3D EA ED %3D EB %3D %3D EC
What is the Maximum moment in kN-m. Given: w = 48, a = 5, b = 4, and c = 1. w kN/m BI b m cm am RD RA A,
b) Determine the reactions at the supports, then draw the Bending Moment Diagram using Force Method. Assume A and B are rollers and C is fixed in Figure QI(b). The support at B settles downward 75mm. Take E = 200GPA, I= 200(10°) mm". 30 kN/m B -3.6 m- -3.6 m- Figure QI(b)
What is the Maximum moment in kN-m. Given: w1 = 44, w2 = 13, a = 3, b = 4, and c = 3. w1 kN/m w2 kN/m a m b m cm
The structure rests on a frictionless support at A and pin connected at E. Determine the internal forces at C.
What is the location of the Maximum moment from A in meters. Given: w = 11, a = 1, b = 5, and c 3. w kN/m A CA D -am | B b m cm
2. FORCE METHOD An overhang beam ABC is loaded as shown. Determine the reactions at the supports due to loading and a support settlement of 1 mm at the roller B. Take E = 200 GPa and I = 500(106) mmª. 20KN 20 k /m C 3m Im
Question I The frame in Figure I has a fixed support at D and pinned support at A. The frame has a constant El. Use the method of flexibility coefficient and compute the: a) Flexibility coefficients b) Compatibility equations c) Restraining bending moment at the support A Note: Use the support at D as the redundant 2 kN/m B 40 kN E D 6 m Figure I 4.5 m | 3m 3m + A
X = 193 Y = 93 A = 2 B = 7 C= 9
Determine the reactions for the beam shown in Figure Q6-A. EI is constant. (Use the Moment Distribution Method). |25 kN w=10 kN/m w=10 kN/m -5 m- -3 m- -3 m- -5 m-
What is the location of the Maximum moment from A in meters. Given: w = 19, a 1, b = 6, and c = 1. %3! w kN/m A D. Kam CA c m b m
Note: a= 4b= 2