For a = 1.5m, determine the reactions at pin A and roller B. 1800 N/m A 4 m Solution: • There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads respectively: 1. The distributed load on the left part of the beam is equivalent to F₁: o Magnitude of it: F₁ = N; o Location of it: x₁ = m to the right of A; 2. The distributed load on the right part of the beam is equivalent to F2: o Magnitude of it: F2 = N; o Location of it: X₂ = 600 N/m B 1. Reactions on A: 2 Reactions on R • The two supports are replaced by corresponding reactions: → m to the right of A;

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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**Transcription of the Image on Distributed Loads on a Beam:**

---

**Solution:**

There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads respectively:

1. **The distributed load on the left part of the beam is equivalent to F₁:**
   - Magnitude of it: F₁ = _____ N;
   - Location of it: x₁ = _____ m to the right of A;

2. **The distributed load on the right part of the beam is equivalent to F₂:**
   - Magnitude of it: F₂ = _____ N;
   - Location of it: x₂ = _____ m to the right of A;

- **The two supports are replaced by corresponding reactions:**
  1. Reactions on A: 
     - (Dropdown)
  2. Reactions on B:
     - (Dropdown)

- **Equilibrium equations:**
  1. ΣFₓ = 0: Aₓ = _____;
  2. ΣMₐ = 0: Bᵧ = _____ N;
  3. ΣMᵦ = 0: Aᵧ = _____ N;

---

**Explanation:**

The document outlines a problem involving two distributed loads on a beam. The goal is to replace these distributed loads with equivalent concentrated loads at specific locations. There are placeholders for students to input the magnitude and location of these forces. Additionally, it involves calculating the reactions at two supports, A and B, and determining the equilibrium conditions with given equations. Students are expected to engage with dropdown menus and fill in the blanks with the appropriate values.
Transcribed Image Text:**Transcription of the Image on Distributed Loads on a Beam:** --- **Solution:** There are two distributed loads acting on the beam, left and right. Replace them with equivalent concentrated loads respectively: 1. **The distributed load on the left part of the beam is equivalent to F₁:** - Magnitude of it: F₁ = _____ N; - Location of it: x₁ = _____ m to the right of A; 2. **The distributed load on the right part of the beam is equivalent to F₂:** - Magnitude of it: F₂ = _____ N; - Location of it: x₂ = _____ m to the right of A; - **The two supports are replaced by corresponding reactions:** 1. Reactions on A: - (Dropdown) 2. Reactions on B: - (Dropdown) - **Equilibrium equations:** 1. ΣFₓ = 0: Aₓ = _____; 2. ΣMₐ = 0: Bᵧ = _____ N; 3. ΣMᵦ = 0: Aᵧ = _____ N; --- **Explanation:** The document outlines a problem involving two distributed loads on a beam. The goal is to replace these distributed loads with equivalent concentrated loads at specific locations. There are placeholders for students to input the magnitude and location of these forces. Additionally, it involves calculating the reactions at two supports, A and B, and determining the equilibrium conditions with given equations. Students are expected to engage with dropdown menus and fill in the blanks with the appropriate values.
**Beam Reactions Calculation**

**Problem Statement:**
For \( a = 1.5 \, \text{m} \), determine the reactions at pin A and roller B.

**Diagram Explanation:**
The image shows a beam supported by a pin at point A on the left and a roller at point B on the right. The beam is subjected to two distributed loads: 1800 N/m on the left part and 600 N/m on the right part. The section between A and B spans 4 m.

**Solution:**

- **Distributed Loads:**
  There are two distributed loads acting on the beam, divided into left and right segments. These loads are replaced by equivalent concentrated loads:

  1. **Left Segment Load:**
     - The distributed load on the left part of the beam is equivalent to \( F_1 \):
       - Magnitude of \( F_1 \): _______ N
       - Location of \( x_1 \): _______ m to the right of A

  2. **Right Segment Load:**
     - The distributed load on the right part of the beam is equivalent to \( F_2 \):
       - Magnitude of \( F_2 \): _______ N
       - Location of \( x_2 \): _______ m to the right of A

- **Support Reactions:**
  The two supports will be replaced by corresponding reactions:

  1. Reactions on A: _______
  2. Reactions on B: _______
Transcribed Image Text:**Beam Reactions Calculation** **Problem Statement:** For \( a = 1.5 \, \text{m} \), determine the reactions at pin A and roller B. **Diagram Explanation:** The image shows a beam supported by a pin at point A on the left and a roller at point B on the right. The beam is subjected to two distributed loads: 1800 N/m on the left part and 600 N/m on the right part. The section between A and B spans 4 m. **Solution:** - **Distributed Loads:** There are two distributed loads acting on the beam, divided into left and right segments. These loads are replaced by equivalent concentrated loads: 1. **Left Segment Load:** - The distributed load on the left part of the beam is equivalent to \( F_1 \): - Magnitude of \( F_1 \): _______ N - Location of \( x_1 \): _______ m to the right of A 2. **Right Segment Load:** - The distributed load on the right part of the beam is equivalent to \( F_2 \): - Magnitude of \( F_2 \): _______ N - Location of \( x_2 \): _______ m to the right of A - **Support Reactions:** The two supports will be replaced by corresponding reactions: 1. Reactions on A: _______ 2. Reactions on B: _______
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