For No. 21-25 When 120 grams of aluminum is reacted with excess chlorine gas and form Aluminum chloride. Al 27 g/mole Cl = 35.5 g/mole 21. What will be the unbalance chemical formula? a. Al + Cl₂ AICI, 4 c. Al + Cl. AICI, d. Al₂ + Cl AICI, b. Al + Cl₂. AICI, 22. What will be the balance formula? a. 2A +3C-2AICI c. 3AI +2C1,-3AICI d. 3Al2 +2C1-3Al₂Ch b. 2A1, +3C12-2AlCl3 23. How many moles of aluminum? a. 8.9 moles c. 4.44 moles b. 8 moles d. 2.22 moles 24. How many moles of Chlorine? a. 6.7 mole c. 5.93 mole b. 2.96 mole d. 2.96 mole 25. How many grams of Aluminum chloride will be produced? a. 277.5 g b. 27.75 g c. 240 g d. 257.7

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For No. 21-25
When 120 grams of aluminum is reacted with excess chlorine gas and form
Aluminum chloride. Al 27 g/mole Cl = 35.5 g/mole
21.
What will be the unbalance chemical formula?
a. Al, Cl₂ AICI₁
+
c. Al + Cl. AICI,
d. Al₂ + Cl AICI,
b. Al + Cl₂. AICI,₁,
22.
What will be the balance formula?
a. 2A +3C-2AICI
c. 3AI +2C1,-3AICI,
d. 3A +2C1-3Al₂Cl₂
b. 2A1, +3C1₂-2Al₂Cla
23.
How many moles of aluminum?
a. 8.9 moles
c. 4.44 moles
d. 2.22 moles
b. 8 moles
24.
How many moles of Chlorine?
a. 6.7 mole
c. 5.93 mole
b. 2.96 mole
d. 2.96 mole
25.
How many grams of Aluminum chloride will be produced?
c. 240 g
a. 277.5 g
b. 27.75 g
d. 257.7
Transcribed Image Text:For No. 21-25 When 120 grams of aluminum is reacted with excess chlorine gas and form Aluminum chloride. Al 27 g/mole Cl = 35.5 g/mole 21. What will be the unbalance chemical formula? a. Al, Cl₂ AICI₁ + c. Al + Cl. AICI, d. Al₂ + Cl AICI, b. Al + Cl₂. AICI,₁, 22. What will be the balance formula? a. 2A +3C-2AICI c. 3AI +2C1,-3AICI, d. 3A +2C1-3Al₂Cl₂ b. 2A1, +3C1₂-2Al₂Cla 23. How many moles of aluminum? a. 8.9 moles c. 4.44 moles d. 2.22 moles b. 8 moles 24. How many moles of Chlorine? a. 6.7 mole c. 5.93 mole b. 2.96 mole d. 2.96 mole 25. How many grams of Aluminum chloride will be produced? c. 240 g a. 277.5 g b. 27.75 g d. 257.7
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