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Consider the reaction. Pb(SO )₂ +2Zn-2ZnSO + Pb If 0.389 mol of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate will be produced in the reaction?

Consider the reaction. Pb(SO )₂ +2Zn-2ZnSO + Pb If 0.389 mol of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate will be produced in the reaction?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How many grams of zinc are there?
**Reaction Analysis** Consider the reaction: \[ \text{Pb(SO}_4\text{)}_2 + 2\text{Zn} \rightarrow 2\text{ZnSO}_4 + \text{Pb} \] **Problem Statement:** If 0.389 moles of zinc react with excess lead(IV) sulfate, how many grams of zinc sulfate will be produced in the reaction? **Solution:** Calculate the mass of zinc sulfate (\( \text{ZnSO}_4 \)): 1. Stoichiometry: According to the balanced equation, 2 moles of Zn produce 2 moles of ZnSO₄. Thus, 1 mole of Zn produces 1 mole of ZnSO₄. 2. Moles of Zn are 0.389, therefore moles of ZnSO₄ produced are also 0.389. 3. Molar mass of ZnSO₄ = 65.38 (Zn) + 32.07 (S) + 4 × 16.00 (O) = 161.45 g/mol. 4. Calculate mass: \( 0.389 \, \text{mol} \times 161.45 \, \text{g/mol} = 62.78 \, \text{g} \). **Answer Box:** Mass: [62.78] g ZnSO₄
Transcribed Image Text:**Reaction Analysis** Consider the reaction: \[ \text{Pb(SO}_4\text{)}_2 + 2\text{Zn} \rightarrow 2\text{ZnSO}_4 + \text{Pb} \] **Problem Statement:** If 0.389 moles of zinc react with excess lead(IV) sulfate, how many grams of zinc sulfate will be produced in the reaction? **Solution:** Calculate the mass of zinc sulfate (\( \text{ZnSO}_4 \)): 1. Stoichiometry: According to the balanced equation, 2 moles of Zn produce 2 moles of ZnSO₄. Thus, 1 mole of Zn produces 1 mole of ZnSO₄. 2. Moles of Zn are 0.389, therefore moles of ZnSO₄ produced are also 0.389. 3. Molar mass of ZnSO₄ = 65.38 (Zn) + 32.07 (S) + 4 × 16.00 (O) = 161.45 g/mol. 4. Calculate mass: \( 0.389 \, \text{mol} \times 161.45 \, \text{g/mol} = 62.78 \, \text{g} \). **Answer Box:** Mass: [62.78] g ZnSO₄
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