A 49.2-gram sample of aluminum metal is mixed with 144.1 grams of rust (Fe2O3) in the reaction shown below in a sealed container. The balances equation is: 2Al + Fe2O3 --> Al2O3 + 2Fe A. How many atoms of aluminum are contained in the reaction vessel? B. How many atoms of aluminum will remain in the container after the reaction? C. What mass of iron metal is produced from this reaction? D. Which substance is the limiting reactant? E. How much limiting reactant is left over after the reaction is performed? F. How much excess reactant is left over after the reaction? G. Calculate the amount of aluminum
Please help :)
A 49.2-gram sample of aluminum metal is mixed with 144.1 grams of rust (Fe2O3) in the reaction shown below in a sealed container. The balances equation is:
2Al + Fe2O3 --> Al2O3 + 2Fe
A. How many atoms of aluminum are contained in the reaction vessel?
B. How many atoms of aluminum will remain in the container after the reaction?
C. What mass of iron metal is produced from this reaction?
D. Which substance is the limiting reactant?
E. How much limiting reactant is left over after the reaction is performed?
F. How much excess reactant is left over after the reaction?
G. Calculate the amount of aluminum oxide that will be produced. Use this answer and the ones above to demonstrate that mass is conserved before and after the reaction occurs.
Trending now
This is a popular solution!
Step by step
Solved in 6 steps