For each of the following electron-transfer reactions, speculate whether the mechanism is outer sphere or inner sphere. Here's the transcription of the chemical equations provided in the image, formatted for educational purposes:---**Chemical Reactions:**(a) \[[IrCl_6]^{2-} + [Co(NH_3)_5(CN)]^{2+} \rightarrow [IrCl_6]^{3-} + [Co(NH_3)_5NC]^{2+}\](b) \[[Co(NH_3)_5(H_2O)]^{2+} + [Cr(H_2O)_6]^{2+} \rightarrow [Co(NH_3)_5(H_2O)]^{3+} + [Cr(H_2O)_6]^{2+}\](c) \[[*Cr(H_2O)_6]^{2+} + [W(CN)_8]^{4-} \rightarrow [Cr(H_2O)_5F]^{2+} + [W(CN)_8]^{3-}\]**Explanation:**- **Equation (a):** This reaction involves the exchange of ligands on cobalt and iridium complexes. The \([IrCl_6]^{2-}\) oxidizes to \([IrCl_6]^{3-}\), while the \([Co(NH_3)_5(CN)]^{2+}\) is reduced to \([Co(NH_3)_5NC]^{2+}\).- **Equation (b):** Shows a redox reaction between cobalt and chromium complexes, where \([Co(NH_3)_5(H_2O)]^{2+}\) is oxidized to \([Co(NH_3)_5(H_2O)]^{3+}\), and \([Cr(H_2O)_6]^{2+}\) remains unchanged.- **Equation (c):** Demonstrates a ligand exchange and redox reaction, where \([*Cr(H_2O)_6]^{2+}\) combines with \([W(CN)_8]^{4-}\) to form \([Cr(H_2O)_5F]^{2+}\) and \([W(CN)_8]^{3-}\).Note: The asterisk (*) and arrow directions may indicate specific experimental conditions or mechanistic pathways in these reactions.--- Please let me know if you need further explanations or illustrations!

A question based on coordination compounds, which is to be accomplished.Q.No. Equation Answer Explanation a [IrCl6]2- + [W(CN)8]4- ⇒ [IrCl6]3- + [W(CN)8]3- Outer sphere There is no exchange of ligand, but only change in Oxidation state. b [Co(NH3)5CN]2+ + [Cr(H2O)6]2+ ⇒[Cr(H2O)5NC]2+ +[Co(NH3)5H2O]2+ Inner sphere There is exchange of ligand. c [*Cr(H2O)6]2+ + [Cr(H2O)5F]2+ ⇒ [*Cr(H2O)5F]2+ + [Cr(H2O)6]2+ Inner sphere There is exchange of ligand.