To test the series.for convergence, youivillUse the limitZComparison testcomparing it to the p seriesK=1Converges or divergesAdd work :)Now by the limit comparison testthe series11Σ₁ 6K² + 4K ²1K=1?16K² + 4K ¹111/ чкеK=14² P= ?

The given series is summation of 1/(6k5+4k11) , k from 1 to infinity.

Answered: for convergence, you vill K=1 use the…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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for convergence, you vill K=1 use the limit comparison test comparing it to the p series. 5 Now by the limit comparison test the series 1 11 26K³ +4K ²² K=1 ? Converges or diverges Add work) 6ks +4K ¹11 Z 4 KP K=1 Rp 21 4K² P= ?