To test this series for convergence n=1 52-3 6n You could use the Limit Comparison Test, comparing it to the series where r Completing the test, it shows the series: O Diverges 8 Converges n=1
To test this series for convergence n=1 52-3 6n You could use the Limit Comparison Test, comparing it to the series where r Completing the test, it shows the series: O Diverges 8 Converges n=1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![To test this series for convergence
\[
\sum_{n=1}^{\infty} \frac{5^n - 3}{6^n}
\]
You could use the Limit Comparison Test, comparing it to the series \(\sum_{n=1}^{\infty} r^n\) where \(r = \Box\)
Completing the test, it shows the series:
- ○ Diverges
- ○ Converges](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54cb8c7a-f5c8-4f70-beb9-4c302d85da57%2Fe865c38b-02d7-45c8-8228-84d483651956%2Fn2eqep_processed.jpeg&w=3840&q=75)
Transcribed Image Text:To test this series for convergence
\[
\sum_{n=1}^{\infty} \frac{5^n - 3}{6^n}
\]
You could use the Limit Comparison Test, comparing it to the series \(\sum_{n=1}^{\infty} r^n\) where \(r = \Box\)
Completing the test, it shows the series:
- ○ Diverges
- ○ Converges
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