Use the limit comparison test to determine whether Σ an = n=11 n=11 lim a. Choose a seriesbn, with terms of the form bn = 1 NP and apply the limit comparison test. Write your answer as a fully simplified fraction. n=11 an bn = lim n→∞0 8 3 8n6n² +11 7+4n4 n +11 converges or diverges. 7n² +4n b. Evaluate the limit in the previous part. Give an exact answer if the limit is a number. Otherwise, enter -∞ or ∞ if the limit is infinite, or enter DNE if the limit does not exist in another way. an lim = 4 n→∞ bn c. By the limit comparison test, does the series converge, diverge, or is the test inconclusive? [Converges

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