For CHCl3(g), Cp = 7.05 + 35.60 x 10-³T - 216.9 x 10-7T² cal mole-1 K-1. Assuming this gas to be ideal, calculate the change in entropy involved in heating 2 moles of the gas from a volume of 100 liters at 500 K to a volume of 70 liters at 700 K.
For CHCl3(g), Cp = 7.05 + 35.60 x 10-³T - 216.9 x 10-7T² cal mole-1 K-1. Assuming this gas to be ideal, calculate the change in entropy involved in heating 2 moles of the gas from a volume of 100 liters at 500 K to a volume of 70 liters at 700 K.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![For CHCl3(g), Cp = 7.05 + 35.60 x 10-³T - 216.9
x 10-7T² cal mole-1 K-1. Assuming this gas to be
ideal, calculate the change in entropy involved in
heating 2 moles of the gas from a volume of 100
liters at 500 K to a volume of 70 liters at 700 K.
ง](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F23e1e3d5-f4a9-424f-9ca9-933f11816050%2F06e0caff-f3db-4de8-b280-68d084cf27d2%2Fqkndsu_processed.png&w=3840&q=75)
Transcribed Image Text:For CHCl3(g), Cp = 7.05 + 35.60 x 10-³T - 216.9
x 10-7T² cal mole-1 K-1. Assuming this gas to be
ideal, calculate the change in entropy involved in
heating 2 moles of the gas from a volume of 100
liters at 500 K to a volume of 70 liters at 700 K.
ง
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