For all A, B ∈ F with A ⊂ B holds P(A) ≤ P(B). Provide a proof, I know the following is given but I cant seem to understand how this is considered a proof P(B) = P(A) + P(B ∩ Ac) ≥ P(A).
For all A, B ∈ F with A ⊂ B holds P(A) ≤ P(B). Provide a proof, I know the following is given but I cant seem to understand how this is considered a proof P(B) = P(A) + P(B ∩ Ac) ≥ P(A).
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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For all A, B ∈ F with A ⊂ B holds
P(A) ≤ P(B).
Provide a proof, I know the following is given but I cant seem to understand how this is considered a proof
P(B) = P(A) + P(B ∩ Ac) ≥ P(A).
Please if able explain the proof a bit further, thank you in advance.
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I dont understand how we go from P(B) = P(A) + P(B ∩ A') to P(B) ≥ P(A)
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