For a gas-phase reaction 2NO(g) +H2(g) N2O(g) +H2O(g), the rate law can be expresseddp (N₂O)asdtkpop₂The data in table have been obtainedRunp°(NO)/kPa p°(H₂)/kPa Half-time/sT/K180.01.3319.21093280.02.6619.2109331.3380.0830109342.6680.04151093580.01.33101113(The runs are at constant temperature and volume)(a) Determine the order of the reaction (a and b) with explanation.(b) Estimate k at 1093 K.

(a) Determine the order of the reaction (a and b) with explanation. Determining the Order of the…

Answered: For a gas-phase reaction 2NO(g) +H2(g)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The reaction described by H, (g) + 1,(g) → 2 HI(g) has an experimentally determined rate law of rate = k [H2][I2] Some proposed mechanisms for this reaction are: Mechanism A (1) H, (g) + L,(g) 2 HI(g) (one-step reaction) Mechanism B (1) 1,(g) =2 1(g) (fast, equilibrium) k_1 (2) H, (g) + 2 I(g) –→ 2 HI(g) (slow) Mechanism C (1) I, (g) = 2 I(g) (fast, equilibrium) k_ k, (2) I(g) + H, (g) –→ HI(g)+H(g) (slow) (3) H(g)+I(g) → HI(g) (fast) Which of these mechanisms are consistent with the observed rate law? O mechanism A O mechanism B O mechanism C In 1967, J. H. Sullivan showed that this reaction was dramatically catalyzed by light when the energy of the light was sufficient to break the I-I bond in an I, molecule. Which mechanism or mechanisms are consistent with both the rate law and this additional observation? O mechanism B O mechanism C O mechanism A
Concentration-Time Relationships (See Section 15.4 and Examples 15.5-15.7.) 15. The rate equation for the hydrolysis of sucrose to fruc- tose and glucose CRH2O1(aq) + H¿O(€) → 2 C,H12O6(aq) is -A[sucrose]/At = k[C¡2H2O1]. After 27 minutes %3D at 27 °C, the sucrose concentration decreased from 0.0146 M to 0.0132 M. Find the rate constant, k.
for this reaction (including orders). Also give the overall order for this reaction: rate law: overall order = %3D 3. Calculate the rate constant, k, for this reaction (use the data from Experiment #1, show all your work): wollood 4. Explain exactly what experiment(s) must be performed in order to
For the gas phase decomposition of ethyl acetate, CH;COOC,H,–CH,COOH + C2H4 the rate constant has been determined at several temperatures. When In k -1 in s is plotted against the reciprocal of the Kelvin temperature, the resulting linear plot has a slope of -2.41x10* K and a y-intercept of 28.8. The activation energy for the gas phase decomposition of ethyl acetate is kJ/mol.
For a first-order reaction k A + B time t = 0 s 4.878 1.004 M time t = 19.84 s ? M when k = 0.030329 s-1 what is the concentration of B above in the question mark= _M? 3 sig. fig. normal format. Try to plot concentrations of A, B and rate over time in Excel.
The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line, y = mz +b. • Part A Order Integrated Rate Law Graph Slope [A] =- kt + [A]Jo -kt + In[A]o In[A] vs. t + = kt + TAT [A] vs. t -k The reactant concentration in a zero-order reaction was 7.00x102 M after 170 s and 3.00x102 M after 380 s. What is the rate constant for this reaction? 1 In[A] = -k Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a multiplication dot or a dash. 1 - vs t JA 2 • View Available Hint(s) ? koih = Value Units Submit Prevlous Anawera Part B Complete previous part(s) • Part C The reactant concentration in a first-order reaction was 6.60x102 Mafter 30.0 s and 7.70x10 Mafter 100 s. What is the rate constant for this reaction? Express your answer with the appropriate units. Indicate the multiplication of units, as necessary, explicitly either with a…
tab esc slock ||| = OKINETICS AND EQUILIBRIUM Writing the rate law implied by a simple mechanism with an initi.... Suppose the formation of dinitrogen pentoxide proceeds by the following mechanism: step elementary reaction 1 NO₂ (g) + O₂ (g). -NO₂(g) + O₂(g) k₁ 2 NO₂ (g) + NO₂ (g) → N₂O5 (g) k₂ Suppose also k₁ «k₂. That is, the first step is much slower than the second. Write the balanced chemical equation for the overall chemical reaction. BE 1 Write the experimentally- observable rate law for the overall chemical reaction. Note: your answer should not contain the concentrations of any intermediates. Explanation Q A @ 2 Check W S X # 3 E 0 rate = k 14 D $ 4 rate constant > R F % 5 © Stv T MacBook Pro 6 G We Y & 7 H 0-0 U 00 Ⓒ2022 McGraw Hill LLC. All R You * 00 00 8 S a (
Please solve correctly, find value of x,y,z

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