For a discrete-time signal x[n] and its phase spectrum X(e^jw) (shown in graph form in attached images), the signals x_p[n] and x_d[n] (shown in equation form in attached images) result from sampling x[n] with a sampling period of 2 and decimating x[n] by a factor of 2, respectively. Draw the graphs of x_p[n] and x_d[n] as well as their phase spectrums, X_p(e^jw) and X_d(e^jw).
For a discrete-time signal x[n] and its phase spectrum X(e^jw) (shown in graph form in attached images), the signals x_p[n] and x_d[n] (shown in equation form in attached images) result from sampling x[n] with a sampling period of 2 and decimating x[n] by a factor of 2, respectively. Draw the graphs of x_p[n] and x_d[n] as well as their phase spectrums, X_p(e^jw) and X_d(e^jw).
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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For a discrete-time signal x[n] and its phase spectrum X(e^jw) (shown in graph form in attached images), the signals x_p[n] and x_d[n] (shown in equation form in attached images) result from sampling x[n] with a sampling period of 2 and decimating x[n] by a factor of 2, respectively. Draw the graphs of x_p[n] and x_d[n] as well as their phase spectrums, X_p(e^jw) and X_d(e^jw).
![xp[n] =
[x[n],
0,
n = 0, +2, +4, ...
n = 1, ±3, ...
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Transcribed Image Text:xp[n] =
[x[n],
0,
n = 0, +2, +4, ...
n = 1, ±3, ...
x₁ [n] = x[2n]
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