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In the given question Wa = V3 radls and § = 0. 6 which means the system is under damped system. Damped frequency wa=wn V1 – =V3• V1 - 0.6 wa=1. 3856 radls 1. Time to reach its peak overshoot 3.14 1.3856 = 2. 267 sec tp Peak overshoot value Mp=e *0.6 =e Mp=0. 09478 2. Time to reach its third peak overshoot 5*3.14 = 11.336 sec 1.3856 tp Third peak overshoot value Mp=e _Vi Vi-062 =e Mp=7. 65 * 106

In the given question Wa = V3 radls and § = 0. 6 which means the system is under damped system. Damped frequency wa=wn V1 – =V3• V1 - 0.6 wa=1. 3856 radls 1. Time to reach its peak overshoot 3.14 1.3856 = 2. 267 sec tp Peak overshoot value Mp=e *0.6 =e Mp=0. 09478 2. Time to reach its third peak overshoot 5*3.14 = 11.336 sec 1.3856 tp Third peak overshoot value Mp=e _Vi Vi-062 =e Mp=7. 65 * 106

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Graphically, sketch the output response of the system showing all the values calculated the image: Then state the type of damped system does this represent, and what would be its time constant?

In the given question Wn = V3 radls and = 0.6 which means the system is under damped system. Damped frequency wa=wn V1 – =V3* V1 - 0.6 Wa=1. 3856 radls 1. Time to reach its peak overshoot 3.14 = 2. 267 sec tp = 1.3856 Peak overshoot value Mp=e 0,6 =e Mp=0. 09478 2. Time to reach its third peak overshoot 5x Ip = Wd 5*3.14 – 11.336 sec 1.3856 Third peak overshoot value Mp=e Sta*0.6 1-06 =e Mp=7. 65 * 10-6
Transcribed Image Text:In the given question Wn = V3 radls and = 0.6 which means the system is under damped system. Damped frequency wa=wn V1 – =V3* V1 - 0.6 Wa=1. 3856 radls 1. Time to reach its peak overshoot 3.14 = 2. 267 sec tp = 1.3856 Peak overshoot value Mp=e 0,6 =e Mp=0. 09478 2. Time to reach its third peak overshoot 5x Ip = Wd 5*3.14 – 11.336 sec 1.3856 Third peak overshoot value Mp=e Sta*0.6 1-06 =e Mp=7. 65 * 10-6
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