For a brick in the shape of a finite cylinder with a triangular cross section (as is used at the junction of two orthogonal walls), with vertices at (0, 0, 0) m, (0, 0, 0.10) m, (0, 0.20, 0) m, (0, 0.20, 0.10) m, (0.20, 0, 0) m, and (0.20, 0, 0.10) m, the temperature distribution (in Cartesian coordinates) is T(z,y,z,1)=(8xy m¹+12yz m-¹ +9zts-¹) Cm-¹ Compute the heat transfer rate to the brick as a function of time. (Using the ME 300 sign convention, this will be a positive quantity if the net flow of heat is into the brick.) Use * = 0.60 W/(mK).

For a brick in the shape of a finite cylinder with a triangular cross section (as is used at the junction of two orthogonal walls), with vertices at (0, 0, 0) m, (0, 0, 0.10) m, (0, 0.20, 0) m, (0, 0.20, 0.10) m, (0.20, 0, 0) m, and (0.20, 0, 0.10) m, the temperature distribution (in Cartesian coordinates) is T(z,y,z,1)=(8xy m¹+12yz m-¹ +9zts-¹) Cm-¹ Compute the heat transfer rate to the brick as a function of time. (Using the ME 300 sign convention, this will be a positive quantity if the net flow of heat is into the brick.) Use * = 0.60 W/(mK).

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter3: Transient Heat Conduction

Section: Chapter Questions

Problem 3.4P

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