Following is a list of some Boolean expressions. Carefully go through each one of them and determine whether they evaluate to true or false. Expression Answer A: ( (count == 0) && (limit < 20)) B: ( count == 0 && limit < 20 ) C: ( (limit > 12) || (count < 5) ) D: ( !(count == 5) ) E: ( (count == 1) && (x < y) ) F: ( (count < 10) || (x < y) ) G: ( !( ((count < 10) || (x < y)) && (count >= 0)) ) H: ( ((limit/count) > 7) || (limit < 20) ) I: ( (limit < 20) || ((limit/count)> 7) ) J: ( ((limit/count) > 7) && (limit < 0) ) K: ( (limit < 0) && (( limit/count) > 7) ) L: ( (5 && 7) + (!6) ) Now, create a file ex41.cpp and cut and paste the following program in it. Compile and run the program and see how well your answers to the above expressions match the program's output. // ex41.cpp - This program illustrates the Boolean expressions and the // order of precedence #include<iostream> using namespace std; int main() { int count = 0, limit = 10; int x,y; cout << "a " << ( (count == 0)&& (limit < 20)) << "\n"; cout << "b " << ( count == 0 && limit < 20 ) << "\n"; cout << "c " << ( (limit > 12) || (count < 5) ) << "\n"; cout << "d " << ( !(count == 5) ) << "\n"; cout << "e " << ( (count == 1)&& (x < y) ) << "\n"; cout << "f " << ( (count < 10) || (x < y) ) << "\n"; cout << "g " << ( !( ((count < 10) || (x < y)) && (count >= 0)) ) << "\n"; cout << "h " << ( ((limit/count)> 7) || (limit < 20) ) << "\n"; cout << "i " << ( (limit < 20) || ((limit/count) > 7) ) << "\n"; cout << "j " << ( ((limit/count)> 7) && (limit < 0) ) << "\n"; cout << "k " << ( (limit < 0) && (( limit/count) > 7) ) << "\n"; cout << "l " << ( (5 && 7) + (!6) ) << "\n"; return 0; } Write your answers through comments. Note that some of the statements may cause run-time errors. Find those statements and explain why the errors have happened. To make the program go to the next statement, simply comment (//) the line that causes the run-time error. Recompile and run the program again until all lines that cause a run-time error are commented. What is the difference between h and i? Would it make any difference if in "j" we switch the first and the second statements, i.e., we use: cout << "j " << ( (limit < 0) && ((limit/count) > 7) ) << "\n"; Exercise 4.1Following is a list of some Boolean expressions. Carefully go through each one of them anddetermine whether they evaluate to true or false.ExpressionA: ((count=0) && (limit <20))B: (count == 0 && limit <20)C: ((limit > 12) || (count <5))D: (!(count=5))E: ((count == 1) && (x= 0)))H: (((limit/count) >7) || (limit <20))I: ((limit <20) || ((limit/count)> 7))J: (((limit/count) >7) && (limit < 0))K: ((limit <0)&&((limit/count) > 7))L: ((5 && 7) + (16))Now, create a file ex41.cpp and cut and paste the following program in it. Compile and runthe program and see how well your answers to the above expressions match the program'soutput.// ex41.cpp - This program illustrates the Boolean expressions and the// order of precedence#includeusing namespace std;Answerint main(){int count = 0, limit= 10;int x,y:cout << "a "<<((count == 0)&& (limit <20)) << "\n";cout << "b"<<(count == 0 && limit <20) << "\n";cout << "e "<<((limit > 12) || (count <5) ) << "\n"cout << "d" <<(!(count=5)) << "\n";cout << "e "<<((count == 1)&& (x= 0))) << "\n";cout << "h"<<(((limit/count)> 7) || (limit <20)) << "\n";cout << "i "<<((limit <20) || ((limit/count) > 7)) << "\n";cout << "j"<<(((limit/count)> 7) && (limit < 0)) << "\n";cout << "k"<<((limit < 0) && (( limit/count) > 7)) << "\n";cout << "1 "<<((5 && 7) + (!6) ) << "\n";return 0;}Write your answers through comments. Write your answers through comments.Note that some of the statements may cause run-time errors. Find those statements and explain whythe errors have happened. To make the program go to the next statement, simply comment (//) theline that causes the run-time error. Recompile and run the program again until all lines that cause arun-time error are commented.What is the difference between h and i?Would it make any difference if in "j" we switch the first and the second statements, i.e., we use:cout << "j "<<((limit < 0) && ((limit/count) >7) ) << "\n";

C++: C++ is a general purpose object oriented programming language. It was developed by Bjarne…

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Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Following is a list of some Boolean expressions. Carefully go through each one of them and determine whether they evaluate to true or false. Expression Answer A: ( (count == 0) && (limit < 20)) B: ( count == 0 && limit < 20 ) C: ( (limit > 12) || (count < 5) ) D: ( !(count == 5) ) E: ( (count == 1) && (x < y) ) F: ( (count < 10) || (x < y) ) G: ( !( ((count < 10) || (x < y)) && (count >= 0)) ) H: ( ((limit/count) > 7) || (limit < 20) ) I: ( (limit < 20) || ((limit/count)> 7) ) J: ( ((limit/count) > 7) && (limit < 0) ) K: ( (limit < 0) && (( limit/count) > 7) ) L: ( (5 && 7) + (!6) ) Now, create a file ex41.cpp and cut and paste the following program in it. Compile and run the program and see how well your answers to the above expressions match the program's output. // ex41.cpp - This program illustrates the Boolean expressions and the // order of precedence #include<iostream> using namespace std; int main() { int count = 0, limit = 10; int x,y; cout << "a " << ( (count == 0)&& (limit < 20)) << "\n"; cout << "b " << ( count == 0 && limit < 20 ) << "\n"; cout << "c " << ( (limit > 12) || (count < 5) ) << "\n"; cout << "d " << ( !(count == 5) ) << "\n"; cout << "e " << ( (count == 1)&& (x < y) ) << "\n"; cout << "f " << ( (count < 10) || (x < y) ) << "\n"; cout << "g " << ( !( ((count < 10) || (x < y)) && (count >= 0)) ) << "\n"; cout << "h " << ( ((limit/count)> 7) || (limit < 20) ) << "\n"; cout << "i " << ( (limit < 20) || ((limit/count) > 7) ) << "\n"; cout << "j " << ( ((limit/count)> 7) && (limit < 0) ) << "\n"; cout << "k " << ( (limit < 0) && (( limit/count) > 7) ) << "\n"; cout << "l " << ( (5 && 7) + (!6) ) << "\n"; return 0; } Write your answers through comments. Note that some of the statements may cause run-time errors. Find those statements and explain why the errors have happened. To make the program go to the next statement, simply comment (//) the line that causes the run-time error. Recompile and run the program again until all lines that cause a run-time error are commented. What is the difference between h and i? Would it make any difference if in "j" we switch the first and the second statements, i.e., we use: cout << "j " << ( (limit < 0) && ((limit/count) > 7) ) << "\n";

Exercise 4.1
Following is a list of some Boolean expressions. Carefully go through each one of them and
determine whether they evaluate to true or false.
Expression
A: ((count=0) && (limit <20))
B: (count == 0 && limit <20)
C: ((limit > 12) || (count <5))
D: (!(count=5))
E: ((count == 1) && (x<y))
F: ((count <10)| (x<y))
G: (!(((count <10) || (x<y))&& (count >= 0)))
H: (((limit/count) >7) || (limit <20))
I: ((limit <20) || ((limit/count)> 7))
J: (((limit/count) >7) && (limit < 0))
K: ((limit <0)&&((limit/count) > 7))
L: ((5 && 7) + (16))
Now, create a file ex41.cpp and cut and paste the following program in it. Compile and run
the program and see how well your answers to the above expressions match the program's
output.
// ex41.cpp - This program illustrates the Boolean expressions and the
// order of precedence
#include<iostream>
using namespace std;
Answer
int main()
{
int count = 0, limit= 10;
int x,y:
cout << "a "<<((count == 0)&& (limit <20)) << "\n";
cout << "b"<<(count == 0 && limit <20) << "\n";
cout << "e "<<((limit > 12) || (count <5) ) << "\n"
cout << "d" <<(!(count=5)) << "\n";
cout << "e "<<((count == 1)&& (x<y)) << "\n";
cout << "f "<<((count <10) || (x<y)) << "\n";
cout << "g "<<(!(((count <10) || (x<y)) && (count >= 0))) << "\n";
cout << "h"<<(((limit/count)> 7) || (limit <20)) << "\n";
cout << "i "<<((limit <20) || ((limit/count) > 7)) << "\n";
cout << "j"<<(((limit/count)> 7) && (limit < 0)) << "\n";
cout << "k"<<((limit < 0) && (( limit/count) > 7)) << "\n";
cout << "1 "<<((5 && 7) + (!6) ) << "\n";
return 0;
}
Write your answers through comments.

Write your answers through comments.
Note that some of the statements may cause run-time errors. Find those statements and explain why
the errors have happened. To make the program go to the next statement, simply comment (//) the
line that causes the run-time error. Recompile and run the program again until all lines that cause a
run-time error are commented.
What is the difference between h and i?
Would it make any difference if in "j" we switch the first and the second statements, i.e., we use:
cout << "j "<<((limit < 0) && ((limit/count) >7) ) << "\n";

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