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Find a counterexample for each statement. (a) If n is prime, then 2 - 1 is prime. (Enter an answer where n < 200.) n = 11 (b) Every triangle has at least one obtuse angle. (An angle is obtuse if it has measure greater than 90°.) O an 80°, 80°, 80° triangle O a 15°, 25°, 140° triangle O a 120°, 30°, 30° triangle O a 35°, 95°, 50° triangle a 60°, 60°, 60° triangle

Find a counterexample for each statement. (a) If n is prime, then 2 - 1 is prime. (Enter an answer where n < 200.) n = 11 (b) Every triangle has at least one obtuse angle. (An angle is obtuse if it has measure greater than 90°.) O an 80°, 80°, 80° triangle O a 15°, 25°, 140° triangle O a 120°, 30°, 30° triangle O a 35°, 95°, 50° triangle a 60°, 60°, 60° triangle

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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also divides n in?

Find a counterexample for each statement. (a) If n is prime, then 2 - 1 is prime. (Enter an answer where n < 200.) 11 n = (b) Every triangle has at least one obtuse angle. (An angle is obtuse if it has measure greater than 90°.) O an 80°, 80°, 80° triangle O a 15°, 25°, 140° triangle O a 120°, 30°, 30° triangle O a 35°, 95°, 50° triangle a 60°, 60°, 60° triangle (c) For all real numbers x, x² 2 x. x = 1 X (d) For every positive nonprime integer n, if some prime p divides n, then some other prime q (with q = p) also divides n. n =
Transcribed Image Text:Find a counterexample for each statement. (a) If n is prime, then 2 - 1 is prime. (Enter an answer where n < 200.) 11 n = (b) Every triangle has at least one obtuse angle. (An angle is obtuse if it has measure greater than 90°.) O an 80°, 80°, 80° triangle O a 15°, 25°, 140° triangle O a 120°, 30°, 30° triangle O a 35°, 95°, 50° triangle a 60°, 60°, 60° triangle (c) For all real numbers x, x² 2 x. x = 1 X (d) For every positive nonprime integer n, if some prime p divides n, then some other prime q (with q = p) also divides n. n =
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