Find a counterexample for each statement.(a) If n is prime, then 2 - 1 is prime. (Enter an answer where n < 200.)n =(b) Every triangle has at least one obtuse angle. (An angle is obtuse if it has measure greater than 90°.)an 80°, 80°, 80° triangleO a 15°, 25°, 140° trianglea 120°, 30°, 30° triangleO a 35°, 95°, 50° triangleO a 60°, 60°, 60° triangle(c) For all real numbers x, x² > x.X =(d) For every positive nonprime integer n, if some prime p divides n, then some other prime g (with q = p) also divides n.n =

Find a counterexample for each statement. (a) If n is prime, then 2 - 1 is prime. (Enter an answer where n < 200.) n = (b) Every triangle has at least one obtuse angle. (An angle is obtuse if it has measure greater than 90°.) O an 80°, 80°, 80° triangle O a 15°, 25°, 140° triangle O a 120°, 30°, 30° triangle O a 35°, 95°, 50° triangle O a 60°, 60°, 60° triangle (c) For all real numbers x, x² >x. X =

Find a counterexample for each statement. (a) If n is prime, then 2 - 1 is prime. (Enter an answer where n < 200.) n = (b) Every triangle has at least one obtuse angle. (An angle is obtuse if it has measure greater than 90°.) O an 80°, 80°, 80° triangle O a 15°, 25°, 140° triangle O a 120°, 30°, 30° triangle O a 35°, 95°, 50° triangle O a 60°, 60°, 60° triangle (c) For all real numbers x, x² >x. X =

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 output: 1712 is a leap year. input: 1913 output: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.def is_leap_year(user_year) My Code: def is_leap_year(user_year):if((user_year % 4 == 0 and user_year % 100 != 0) or (user_year % 400 == 0)):print("{} is a leap…
p.252, icon at Example 2 #1. Certain rules allow us to determine by inspection when a positive integer n is divisible by a positive integer k. For example, 5❘n if and only if n ends in the digit 5 or 0. Similarly, 2❘n if and only if n ends in one of the digits 0, 2, 4, 6, 8. There is also a rule to determine divisibility by 3: 3❘n if and only if the sum of the digits in n is divisible by 3. For example 3 | 478, 125 because the sum of the six digits in 478, 125 is 27, which is divisible by 3. Why does the rule work?
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A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 - leap year Ex: If the input is: 1913 the output is: 1913 - not a leap year
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