A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.def is_leap_year(user_year) Note: This is a lab from a previous chapter that now requires the use of a function.   def is_leap_year(user_year):    if (user_year % 4) == 0:        result = "{0} is a leap year.".format(user_year)    elif (user_year % 100) == 0:        result = "{0} is a leap year.".format(user_year)    elif (user_year % 400) == 0:        result = "{0} is a leap year.".format(user_year) else:    result = "{0} is not a leap year.".format(user_year)    return resultif __name__ == '__main__':    user_year = int(input())    leap_year = is_leap_year(user_year)    print(leap_year)