Five equally charged positive pith balls are placed symmetrical around a semicircle of radius "R". The semicircle is inthe upper half of the x-y plane. The strength of the Efield at the center of the semicircle due to ONE point charge is5.00 N4. Answer the following questions about the electric field at the center of the semicircle.a) Draw a picture of the charge distributionb) Find the direction of the resultant E-field at the center of the semicircle. Show all work.c) Find the magnitude of the resultant E-field at the center of the semicircle, Show all work

(a) picture of the charge distribution(b) Since all charges are equal the magnitude of the electric field due to each charge must be the same. Electric field E1 and E5 are equal and opposite. The horizontal components of E2 and E4 are equal and opposite but their vertical components add up. Thus, the direction of the net electric field is downward.(c) Magnitude of the net electric field Enet=E3+E2y+E4y=E+Esin180°5+Esin180°5=E1+2sin36°=5.00 N1+2sin36°=10.877 N≈10.9 N

Answered: Five equally charged positive pith…