Problem 1: A positive charge of magnitude Q1 = 0.85 nC is located at the origin. A negative charge Q₂ = -9.5 nC is located on the positive x-axis at x = 14 cm from the origin. The point P is located y = 19 cm above charge Q2. y 19₁ Part (a) Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. Ex1 = 81.44 Part (b) Calculate the y-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. R Part (c) Calculate the y-component of the electric field at point P due to the Charge Q₂. Write your answer in units of N/C. Part (d) Calculate the y-component of the electric field at point P due to both charges. Write your answer in units of N/C. Port (a) Calculate the magnitude of the electric field at point D due to both chorgas Write your onewer in units of NIC X P Q₂
Problem 1: A positive charge of magnitude Q1 = 0.85 nC is located at the origin. A negative charge Q₂ = -9.5 nC is located on the positive x-axis at x = 14 cm from the origin. The point P is located y = 19 cm above charge Q2. y 19₁ Part (a) Calculate the x-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. Ex1 = 81.44 Part (b) Calculate the y-component of the electric field at point P due to charge Q1. Write your answer in units of N/C. R Part (c) Calculate the y-component of the electric field at point P due to the Charge Q₂. Write your answer in units of N/C. Part (d) Calculate the y-component of the electric field at point P due to both charges. Write your answer in units of N/C. Port (a) Calculate the magnitude of the electric field at point D due to both chorgas Write your onewer in units of NIC X P Q₂
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answer parts b, c, d
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Step 1: Define electric field due to a point charge:
VIEWStep 2: (b) Calculate the y-component of the electric field at point P due to charge Q1.
VIEWStep 3: (c) Calculate the y-component of the electric field at point P due to charge Q2.
VIEWStep 4: Calculate the net y-component of the electric field at point P due to both charges.
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