Finding the expanded depth of the uniform medium Filter medium sand grains (0.4mm in diameter) Ψ= 0.85 specific gravity= 2.65 depth of the bed=0.67m porosity=0.4 T=20 C μ= 1.002 .10-3N.s / m2 ρw=998 .2 kg / m3 Determine the required backwash velocity to expand the bed to a porosity of 0.7.

Q: A 20 m thick clay layer is sandwiched between a silty sand layer and a gravelly sand layer. The…

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Q: data are given from the laboratory consolidation test. e₁ = 1.10 σ= 65.0 kN/m² e₂ = σ₂=240.0 kN/m²…

A: The Compression Index (Cc) is equal to the slope of the graph of pressure versus void ratio (log…

Q: A simple of dry sand is subjected to a triaxial test. During the test if deviator stress and cell…

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Q: 11.17 The time for 75% consolidation of a 25-mm clay specimen (drained at top and bottom) in the…

A: Given Data: The thickness of the clay specimen is Hs=25 mm. The thickness of clay layer in the field…

Q: The relationship between the specific gravity of sand (G) and the hydraulic gradient (i) to initiate…

A: Porosity n=30%=0.30   It is needed to find the relationship between specific gravity G &…

Q: coefficient of consolidation of 20 ft2 /yr is given for the singly-drained clay layer. This layer…

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Q: Refer to the soil profile shown in figure below. A laboratory consolidati the results: o'c = 100 kPa…

A: Dry unit weight of sand γdsand=Gγw1+e=2.669.811+0.55=16.835kNm3Sat unit weight of sand…

Q: A consolidated un-drained triaxial test was performed on a specimen of saturated clay with a kg…

A: Given : σ3 = 2.0 kg/cm2 σ1 - σ3 = 2.8 kg/cm2 u = 1.8 kg/cm2 θ = 57 o This is a problem of Soil where…

Q: Given the following consolidation test, plot the e-log p relationship and determine if the clay…

A: The curve of the trend shows that it is an overconsolidated curve

Q: consolidated clay specimen, the results o 10 lb/ft², Deviator stress at failure = 3,65:

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Q: 2.11 From the soil profile shown in Figure P2.11, determine the total stress, pore water pressure,…

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Q: Elevation (m) 2.0 3.0 5.4 20.6 Very fine wet sand with silt w = 5%, S = 40% w = 12%.S = 100% Fine…

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Q: 4. For a normally consolidated clay, the following values are given. k (cm/sec) 0.45 x 106 e 0.78…

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Q: =) For the soil deposit shown below, determine the maghltu following total stress pore water…

A: Total stress :⇒at z=0σ=0⇒at z=4σ=1.924=7.68tm3⇒at z=11σ=1.924+2.111-4=22.38tm3

Q: Refer to the soil profile shown in Figure P2.12. Determine the total stress, pore water pressure,…

A: For dry sand part,γd=G×γw1+e=2.66×9.811+0.55=   16.84kN/m3                               (…