Find unknown and show ALL work and arrows etc 1D TopSPIN Multiplet TableID Shift (ppm] J[Hz] M2.5300 6.0012 71.0400 6.0012 2C5H100Ketone (From IR)ConnectionJ(1, 0)J(2, 0)Let's Try an Unknown!3.0 29 28 27 26 25 24 23 22 2192.0 1.9 1.81.7 1.6 1.5 1.41.3 1.21.1BRUKER1.0 0.9 0.8 0.7 ppm

Given that, the molecular formula of the unknown compound is C5H10O.The formula of the Double bond…

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Find unknown and show ALL work and arrows etc

1D TopSPIN Multiplet Table
ID Shift (ppm] J[Hz] M
2.5300 6.0012 7
1.0400 6.0012 2
C5H100
Ketone (From IR)
Connection
J(1, 0)
J(2, 0)
Let's Try an Unknown!
3.0 29 28 27 26 25 24 23 22 21
9
2.0 1.9 1.8
1.7 1.6 1.5 1.4
1.3 1.2
1.1
BRUKER
1.0 0.9 0.8 0.7 ppm

Expert Solution

Step 1: Double bond equivalency

Given that, the molecular formula of the unknown compound is C₅H₁₀O.

The formula of the Double bond equivalency is

DBE = (No. of carbon atoms + 1) + ( $fraction numerator N o. space o f space m o n o v a l e n t space a o m space plus space N o. space o f space t r i v a l e n t space a t o m s over denominator 2 end fraction$ ) = (5+1)-(10/2) = (6-5) = 1.

So, the unknown compound has one unsaturation.

Also, given the IR analysis, the unknown compound has a keto group.

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