Find the wave number of a photon having an energy of 2.072 e V. (Given : Charge of an electron = 1.6 x 10 "c velocity of light in air = 3 × 10° m's Plank's %3D -34 constant = 6.63 x 10 * J.s.)
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A: To find-λ0=?(K.E.)max=?Given-ϕ0=4.2 eV=4.2×1.6×10-19 JVs=3 Vc=3×108 m/sh=6.63×10-34 Jse=1.6×10-19 C
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