**Compton Scattering Problem****Description**Given:- \(0.062 \)-nm photons are incident on stationary electrons.**Step 1: Scattering Angle and Wavelength**A scattered photon is observed at \(134^\circ\).**Question:**Find its wavelength, \(\lambda' =\) **6.61e-2** nm, and energy, \(E'_\gamma =\) **18.8** keV.**Step 2: Kinetic Energy of Recoiled Electron****Given:**The kinetic energy of the recoiled electron is \( \text{KE} = \) **1.25** keV.**Step 3: Maximum Kinetic Energy****Question:**What is the maximum kinetic energy of recoiled electrons exposed to these photons?**Answer:**\(\text{KE}_{\text{max}}\) = **[Blank Box]** keV.

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0.062-nm photons are incident on stationary electrons. A scattered photon is observed at 134°. Find its wavelength, 2'= 6.61e-2 nm, and energy, E',= 18.8 kev. The kinetic energy of the recoiled electron is KE= 1.25 kev.

0.062-nm photons are incident on stationary electrons. A scattered photon is observed at 134°. Find its wavelength, 2'= 6.61e-2 nm, and energy, E',= 18.8 kev. The kinetic energy of the recoiled electron is KE= 1.25 kev.

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Concept explainers

Compton effect

The incoming photons' energy must be in the range of an X-ray frequency to generate the Compton effect. The electron does not lose enough energy that reduces the wavelength of scattered photons towards the visible spectrum. As a result, with visible lights, the Compton effect is missing.

Recoil Velocity

The amount of backward thrust or force experienced by a person when he/she shoots a gun in the forward direction is called recoil velocity. This phenomenon always follows the law of conservation of linear momentum.

Question

**Compton Scattering Problem**

**Description**

Given:

- \(0.062 \)-nm photons are incident on stationary electrons.

**Step 1: Scattering Angle and Wavelength**

A scattered photon is observed at \(134^\circ\).

**Question:**
Find its wavelength, \(\lambda' =\) **6.61e-2** nm, and energy, \(E'_\gamma =\) **18.8** keV.

**Step 2: Kinetic Energy of Recoiled Electron**

**Given:**
The kinetic energy of the recoiled electron is \( \text{KE} = \) **1.25** keV.

**Step 3: Maximum Kinetic Energy**

**Question:**
What is the maximum kinetic energy of recoiled electrons exposed to these photons?

**Answer:**
\(\text{KE}_{\text{max}}\) = **[Blank Box]** keV.

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