Find the Thevenin Equivalent circuit at terminals (a, b) across the 1 Ohm rightmost resistor (see red dots), then reconnect the load resistor load to find Vo(t). Note the role that superposition plays. That is, express V = {H1} Vs+ {H2} Is 10 Vs 2Ix 10 ww 10 Is 10 V₁
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- Please someone help me to slove these two problems, and give me an explanation , thank youc) Using minimum number of components, design a voltage divider which can deliver 1 W at 100V, 2W at -50V and 1.6W at -80V. The voltage source has an internal resistance of 200 Q and supplies a current of 100mA. What is the open - circuit voltage of the voltage source? All resistance in ohm.Just like resistors, impedance values can be combined in series or in parallel. We combine them in the same way as combining resistors, i.e., for the series connection: Zeg Z1+22+ Z3+.... For the parallel connection: Zeq = (Z+Z+Z3+...) What is the equivalent impedance of the following circuit? (Hint: you can use scientific calculator or MatLab to perform calculations involving complex numbers.) L 50 £2 300 1000 MO 400 200 102.2+19.8j O 102.2-19.8j -102.2+19.8j O-102.2 19.8j
- RA R3 V2 D. R2 R1 For the above circuit, select ALL the extraordinary nodes that are part of a quasi-supernode. If there are none then select NONE. Note: a supernode is not a quasi-supernode. O NONE B. ODOCircuits Find vth rth and a b power maximum?Shown in the figure below is an electrical circuit containing three resistors and two batteries. I₁ 0= 4 + L . ww R3 R₂ ww 1₂ R₁ ww Write down the Kirchhoff Junction equation and solve it for I, in terms of I₂ and I3. Write the result here: 1₁ = 12-13 R₂=552 R₂ = 132 13 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and follows the perimeter of the circuit diagram clockwise. - IzR3 − LR₁ + 14 + 10 Write down the Kirchhoff Loop equation for a loop that starts at the lower left corner and touches the components 4V, R₂, and R₁. 0 = 4-1₂R₂-11R₁ The resistors in the circuit have the following values: R₁ = 12 Solve for all the following (some answers may be negative): I₁ = 27.78 X Amperes 1₂ = 28.84 X Amperes 13 = 1.060 X Amperes NOTE: For the equations, put in resistances and currents SYMBOLICALLY using variables like R₁,R₂,R3 and 11,12,13. Use numerical values of 10 and 4 for the voltages.
- NoneAn ideal voltage divider consists of only R₁, R2, and the voltage source in series with each other. In practical use, the terminals of the divider has a stray capacitance Cs, making the circuit frequency dependent. The compensating capacitance C₁ is added to the circuit to make V₂/V₁ independent of the frequency again. Determine the value of the compensating capacitance C₁ in terms of R₁, R2, and Cs. + V₁ R1 I'm R2 ww + V₂ CsA component requires 6.3-V across it with a current of 0.3 V. A second component requires 12.6-V at 0.15A. The two components are connected in series. What is the value of resistor that must be connected across the 12.6-V component to allow it to operate properly when in series with the 6.3-V component?
- Please asapPlease answer the below question explaining each step Solve using nodal analysis (preferably) and please see whether my working for nodal analysis is correct or not = 0.0238A from A to BConsider the series-parallel circuit shown in the figure below with various multimeters connected in the circuit. Assum that XMM1 has been configured in ammeter mode, and XMM2 has been configured in voltmeter mode. XMM1 R1 1kQ XMM2 R2 R3 V1 1kQ 1kQ 12V 3.1: Redraw the circuit replacing XMM1 and XMM2 by their equivalent circuit models 3.2: Assume that XMM2 was incorrectly configured in ammeter mode. Redraw the equivalent circuit from 3.1 and compute the current that would be measured by the ammeter in this scenario. Hil-