AAstion listuestion 1uestion 2question 3uestion 4uestion 5uestion 6uestion 74:41uestion 8uestion 9<mylab.pearson.comKFind the standard deviation, s, of sample data summarized in the frequency distribution table below by using theformula below, where x represents the class midpoint, f represents the class frequency, and n represents the totalnumber of sample values. Also, compare the computed standard deviation to the standard deviation obtained fromthe original list of data values, 11.1.SH[π[Σ(10x?)] - [Σ(-x)n(n-1)IntervalFrequency30-36237-43 44-50 | 51-57 | 58-647+24 T 8 T 31Standard deviation = 10.7 (Round to one decimal place as needed.)Consider a difference of 20% between two values of a standard deviation to be significant. How does this computedvalue compare with the given standard deviation, 11.17XA. The computed value is significantly less than the given value.65-71 72-78 D29OB. The computed value is significantly greater than the given value.*C. The computed value is not significantly different from the given value.An

Interval Frequency 30-36 2 37-43 2 44-50 7 51-57 4 58-64 8 65-71 31 72-78 29

Answered: Find the standard deviation, s, of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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Noise Levels in Hospitals In a hospital study, it was found that the standard deviation of the sound levels from 25 areas designated as "casualty doors" was 6.0 dBA and the standard deviation of 21 areas designated as operating theaters was 3.7= dBA. At a0.05, can you substantiate the claim that there is a difference in the standard deviations? Use σ1 for the standard deviation of the sound levels from areas designated as "casualty doors." (a)State the hypotheses and identify the claim. H0: H1: This hypothesis test is a one tailed/two-tailed test. (b)Find the critical value. Round the answer to two decimal places. Critical value= (c)Compute the test value. Round the F score value to two decimal places as needed. F= (d)Make the decision. Reject/do not rejecct the null hypothesis. (e)Summarize the results. There is/is not enough evidence to support the claim that there is/is not a difference in the standard deviations of the sound levels.
The lengths of pregnancies in a small rural village are normally distributed with a mean of 267 days and a standard deviation of 14 days. A distribution of values is normal with a mean of 267 and a standard deviation of 14. What percentage of pregnancies last fewer than 274 days? P(X < 274 days) Let XX represent the full height of certain species of tree. Assume that XX is normally distributed with a mean of 82.1 feet and a standard deviation of 47.9 feet.Find the probability that the full height of a randomly selected tree is greater than 154 feet. P(X>154)
A survey collected data from a random sample of 121 people living in Jade city. The sample average of the distance people travel to reach their workplaces (Y) is 23.28 km and the standard deviation (sy) is 7.48 km. The standard error of the sample average of the distance people travel to reach their workplaces is 68 km. (Round your answer to two decimal places.) Let μy denote the mean of the distance all the people in Jade city travel to reach their workplaces. The p-value of the test Ho: #y #22 km vs. H₁: Hy #22 km is (Round your answer to two decimal places.)
Find the standard deviation for the group of data items. Stems Leaves 0 877858 3302 The standard deviation is (Round to two decimal places as needed.)
Use the formula to find the standard error of the distribution of differences in sample means, ₁ - X₂. Samples of size 105 from Population 1 with mean 86 and standard deviation 13 and samples of size 80 from Population 2 with mean 73 and standard deviation 16 Round your answer for the standard error to two decimal places. standard error =
The mean score on a driving exam for a group of driver's education students is 60 points, with a standard deviation of 3 points. Apply Chebychev's Theorem to the data using k=2. Interpret the results. At least ( )% of the exam scores fall between ( )and ( )
Attenuation is the reduction of the amplitude of a signal, electric current, or other oscillation. With maximum attenuation, a scanner will not be able to read a bar code at a fixed distance. After substantial amount of data collection, a group of instrumentation engineers decided to model a variation of maximum attenuation of scanners as a normal distribution with a mean of 10.1 decibels and standard deviation of 2.7, same unit. What proportion of the products have maximum attenuation greater than 15.1 dB? 0.0718 none of these 0.0322 0.0214
Q.: For the data given in the following frequency distribution table, compute if the nearest error in the data is 1: (a) mean deviation (b) Median (c) Mode (d) Range (e) Variance (f) Standard deviation Classes 150-1 168 - 186- 195 204-213- - 58 Frequency 5 20 20 15 3 1 159-1 67 15 177- 21
An analyst for a transportation metro is asked to examine the time required (x) in minutes for a specific commute route. She records 200 randomly sampled times and finds: Σx = 11,000 and Sxx =1791. Find the average commute time, as well as standard deviation and coefficient of variation.
please help me solve this practice question using excel

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