**Understanding the Central Limit Theorem through Sampling Distribution**In this exercise, we apply the central limit theorem to find the mean and standard error of the mean for the indicated sampling distribution. The objective is to sketch a graph of the sampling distribution based on the given data.**Context:** The per capita consumption of red meat by individuals in a specific country was normally distributed in a recent year. The mean consumption was 101 pounds, with a standard deviation of 38.9 pounds. Random samples of size 20 are drawn from this population, and the mean of each sample is calculated.**Calculations:** - The mean of the sampling distribution (μx̄) is the same as the population mean: - μx̄ = 101- The standard error of the mean (σx̄) is calculated as: - σx̄ = 8.698 (rounded to three decimal places)**Task:** Sketch a graph of the sampling distribution and choose the correct graph from the options below.**Graph Options:**- **A.** A normal distribution centered at 101, with a range approximately between 83.6 and 118.4.- **B.** A normal distribution centered at 101, with a more spread-out range approximately between 74.9 and 127.1.- **C.** A normal distribution far off the expected mean, centered at 8.7, with a range approximately between -92.3 and 109.7.- **D.** A distribution with an even more extreme mean shift, centered at 8.7, with a very wide range approximately between -294.3 and 311.7.The correct choice accurately reflects the calculated mean and standard error, precisely capturing the expected distribution of sample means.

The mean of the sampling distribution is, μx¯=μ=101 Thus, the mean of the sampling distribution is…

Use the central limit theorem to find the mean and standard error of the mean of the indicated sampling distribution. Then sketch a graph of the sampling distribution. The per capita consumption of red meat by people in a country in a recent year was normally distributed, with a mean of 101 pounds and a standard deviation of 38.9 pounds. Random samples of size 20 are drawn from this population and the mean of each sample is determined. H= 101 = 8.698 (Round to three decimal places as needed.) Sketch a graph of the sampling distribution. Choose the correct graph below. OA. В. C. D. 83.6 101 118.4 74.9 101 127.1 -92.3 8.7 109.7 -294.3 8.7 311.7 O 回 O o 包

Use the central limit theorem to find the mean and standard error of the mean of the indicated sampling distribution. Then sketch a graph of the sampling distribution. The per capita consumption of red meat by people in a country in a recent year was normally distributed, with a mean of 101 pounds and a standard deviation of 38.9 pounds. Random samples of size 20 are drawn from this population and the mean of each sample is determined. H= 101 = 8.698 (Round to three decimal places as needed.) Sketch a graph of the sampling distribution. Choose the correct graph below. OA. В. C. D. 83.6 101 118.4 74.9 101 127.1 -92.3 8.7 109.7 -294.3 8.7 311.7 O 回 O o 包

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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