College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem: Calculating Resistance of Aluminum Wire**
Find the resistance of a 78.0-meter length of No. 20 aluminum wire at a temperature of 20°C. The resistivity (\( \rho \)) of the wire is \( 2.83 \times 10^{-6} \, \Omega \cdot \text{cm} \), and the cross-sectional area (A) is \( 2.07 \times 10^{-2} \, \text{cm}^2 \).
**Solution Approach:**
To calculate the resistance (R) of the wire, use the formula:
\[ R = \frac{\rho \cdot L}{A} \]
where:
- \( R \) is the resistance in ohms (\( \Omega \)),
- \( \rho \) is the resistivity in ohm-centimeters (\( \Omega \cdot \text{cm} \)),
- \( L \) is the length of the wire in centimeters (cm),
- \( A \) is the cross-sectional area in square centimeters (\(\text{cm}^2\)).
**Calculate the Resistance:**
1. **Convert Length to Centimeters:**
\[ L = 78.0 \, \text{m} = 7800 \, \text{cm} \]
2. **Substitute the Known Values:**
\[ R = \frac{2.83 \times 10^{-6} \, \Omega \cdot \text{cm} \times 7800 \, \text{cm}}{2.07 \times 10^{-2} \, \text{cm}^2} \]
3. **Solve for R:**
Complete the multiplication and division to find the resistance.
This step-by-step approach will guide students in calculating the resistance of a wire, considering the material properties and dimensions provided.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc463f08e-ec7e-4810-a9a2-5563bca4d00b%2F9f485938-75e1-4a2f-9479-83bb4eb3364e%2F01o7nu6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem: Calculating Resistance of Aluminum Wire**
Find the resistance of a 78.0-meter length of No. 20 aluminum wire at a temperature of 20°C. The resistivity (\( \rho \)) of the wire is \( 2.83 \times 10^{-6} \, \Omega \cdot \text{cm} \), and the cross-sectional area (A) is \( 2.07 \times 10^{-2} \, \text{cm}^2 \).
**Solution Approach:**
To calculate the resistance (R) of the wire, use the formula:
\[ R = \frac{\rho \cdot L}{A} \]
where:
- \( R \) is the resistance in ohms (\( \Omega \)),
- \( \rho \) is the resistivity in ohm-centimeters (\( \Omega \cdot \text{cm} \)),
- \( L \) is the length of the wire in centimeters (cm),
- \( A \) is the cross-sectional area in square centimeters (\(\text{cm}^2\)).
**Calculate the Resistance:**
1. **Convert Length to Centimeters:**
\[ L = 78.0 \, \text{m} = 7800 \, \text{cm} \]
2. **Substitute the Known Values:**
\[ R = \frac{2.83 \times 10^{-6} \, \Omega \cdot \text{cm} \times 7800 \, \text{cm}}{2.07 \times 10^{-2} \, \text{cm}^2} \]
3. **Solve for R:**
Complete the multiplication and division to find the resistance.
This step-by-step approach will guide students in calculating the resistance of a wire, considering the material properties and dimensions provided.
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