(25%) Problem 6: A copper wire has a resistance of 0.495 at 20.0°C, and an iron wire has a resistance of 0.535 2 at the same temperature. DA At what temperature, in degrees Celsius, are their resistances equal? The temperature coefficient of resistivity of copper is 3.9 x 10 (°C), while that for iron is 5.0 x 10-3 (°C)-!
(25%) Problem 6: A copper wire has a resistance of 0.495 at 20.0°C, and an iron wire has a resistance of 0.535 2 at the same temperature. DA At what temperature, in degrees Celsius, are their resistances equal? The temperature coefficient of resistivity of copper is 3.9 x 10 (°C), while that for iron is 5.0 x 10-3 (°C)-!
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![(25%) Problem 6: A copper wire has a resistance of 0.495 2 at 20.0°C, and an iron wire has a resistance of 0.535 2 at the same temperature.
D A At what temperature, in degrees Celsius, are their resistances equal? The temperature coefficient of resistivity of copper is 3.9 x 10-3 (°C)-!, while that for
iron is 5.0 x 10-3 (°C)-!.
T =
sin()
cos()
tan()
9
HOME
cotan()
asin()
acos()
E
4
5
6.
atan()
acotan()
sinh()
1
3
cosh()
tanh()
cotanh()
END
O Degrees O Radians
Vol BACKSPACE
D CLEAR](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fff7f72a6-27ca-4fc6-a195-84c52d046220%2F06bb7c81-76aa-4500-a80e-97fa39bad415%2Fslqiwzl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(25%) Problem 6: A copper wire has a resistance of 0.495 2 at 20.0°C, and an iron wire has a resistance of 0.535 2 at the same temperature.
D A At what temperature, in degrees Celsius, are their resistances equal? The temperature coefficient of resistivity of copper is 3.9 x 10-3 (°C)-!, while that for
iron is 5.0 x 10-3 (°C)-!.
T =
sin()
cos()
tan()
9
HOME
cotan()
asin()
acos()
E
4
5
6.
atan()
acotan()
sinh()
1
3
cosh()
tanh()
cotanh()
END
O Degrees O Radians
Vol BACKSPACE
D CLEAR
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Let at temperature T
Riron = Rcu
.535[1+5×10^-3(T-20)] = .495 [1+3.9×10^-3(T-20)]
.4816+2.675×10^-3T = .4564+1.93×10^-3T
.744×10^-3 T = .0251
T = -33.74°C
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