An aluminum wire has a resistance of 5.50 Q at 10.0°C. Determine its resistance (in Q) at 410°C. The temperature coefficient of resistivity for aluminum wire is 3.90 x 10¬3 (°C)-'. (Assume that the temperature coefficient of resistivity was measured using the reference temperature 20°C.) 8.58

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**Problem:**

An aluminum wire has a resistance of 5.50 Ω at 10.0°C. Determine its resistance (in Ω) at 410°C. The temperature coefficient of resistivity for aluminum wire is 3.90 × 10⁻³ (°C)⁻¹. (Assume that the temperature coefficient of resistivity was measured using the reference temperature 20°C.)

**Solution:**

Resistance calculation box:  
\[ \text{8.58} \, \Omega \]

**Explanation:**

This problem involves calculating the change in resistance of an aluminum wire as temperature changes. The temperature coefficient of resistivity (\(\alpha\)) allows us to determine how much the resistance of a material will increase per degree change in temperature.

**Formula for calculation:**
\[ R_t = R_0 \cdot (1 + \alpha \cdot (T - T_0)) \]

Where:
- \(R_t\) is the resistance at temperature \(T\).
- \(R_0\) is the original resistance (5.50 Ω at 10.0°C).
- \(\alpha\) is the temperature coefficient of resistivity for aluminum (3.90 × 10⁻³ (°C)⁻¹).
- \(T\) is the new temperature (410°C).
- \(T_0\) is the initial temperature (10.0°C).

**Calculation:**

\[ R_t = 5.50 \, \Omega \times (1 + 3.90 \times 10^{-3} \times (410 - 10)) \]

\[ R_t = 5.50 \, \Omega \times (1 + 3.90 \times 10^{-3} \times 400) \]

\[ R_t = 5.50 \, \Omega \times (1 + 1.56) \]

\[ R_t = 5.50 \, \Omega \times 2.56 \]

\[ R_t \approx 14.08 \, \Omega \]

Therefore, the resistance at 410°C is approximately 14.08 Ω. The incorrect value shown in the problem is 8.58 Ω.
Transcribed Image Text:**Problem:** An aluminum wire has a resistance of 5.50 Ω at 10.0°C. Determine its resistance (in Ω) at 410°C. The temperature coefficient of resistivity for aluminum wire is 3.90 × 10⁻³ (°C)⁻¹. (Assume that the temperature coefficient of resistivity was measured using the reference temperature 20°C.) **Solution:** Resistance calculation box: \[ \text{8.58} \, \Omega \] **Explanation:** This problem involves calculating the change in resistance of an aluminum wire as temperature changes. The temperature coefficient of resistivity (\(\alpha\)) allows us to determine how much the resistance of a material will increase per degree change in temperature. **Formula for calculation:** \[ R_t = R_0 \cdot (1 + \alpha \cdot (T - T_0)) \] Where: - \(R_t\) is the resistance at temperature \(T\). - \(R_0\) is the original resistance (5.50 Ω at 10.0°C). - \(\alpha\) is the temperature coefficient of resistivity for aluminum (3.90 × 10⁻³ (°C)⁻¹). - \(T\) is the new temperature (410°C). - \(T_0\) is the initial temperature (10.0°C). **Calculation:** \[ R_t = 5.50 \, \Omega \times (1 + 3.90 \times 10^{-3} \times (410 - 10)) \] \[ R_t = 5.50 \, \Omega \times (1 + 3.90 \times 10^{-3} \times 400) \] \[ R_t = 5.50 \, \Omega \times (1 + 1.56) \] \[ R_t = 5.50 \, \Omega \times 2.56 \] \[ R_t \approx 14.08 \, \Omega \] Therefore, the resistance at 410°C is approximately 14.08 Ω. The incorrect value shown in the problem is 8.58 Ω.
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