Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marblewith a diameter of 1.2 cm. How does the result compare to the actual circumference of 3.8 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 7.5 24.3 4.2 21.7 6.9 4.1 20.7 Circumference 23.6 76.3 13.2 68.2 21.7 12.9 65.0 View the critical values of the Pearson correlation coefficient r. Critical values of the pearson correlation coefficient r n α=0.05 α=0.01 NOTE: To test H0: ρ=0 against H1: ρ≠0, reject H0 if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 5 0.878 0.959 6 0.811 0.917 7 0.754 0.875 8 0.707 0.834 9 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40 0.312 0.402 45 0.294 0.378 50 0.279 0.361 60 0.254 0.330 70 0.236 0.305 80 0.220 0.286 90 0.207 0.269 100 0.196 0.256 n α=0.05 α=0.01 The regression equation is y= ___________+___________x. (Round to five decimal places as needed.) The best predicted circumference for a diameter of 1.2cm is _________cm. (Round to one decimal place as needed.)
Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marblewith a diameter of 1.2 cm. How does the result compare to the actual circumference of 3.8 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 7.5 24.3 4.2 21.7 6.9 4.1 20.7 Circumference 23.6 76.3 13.2 68.2 21.7 12.9 65.0 View the critical values of the Pearson correlation coefficient r. Critical values of the pearson correlation coefficient r n α=0.05 α=0.01 NOTE: To test H0: ρ=0 against H1: ρ≠0, reject H0 if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 5 0.878 0.959 6 0.811 0.917 7 0.754 0.875 8 0.707 0.834 9 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40 0.312 0.402 45 0.294 0.378 50 0.279 0.361 60 0.254 0.330 70 0.236 0.305 80 0.220 0.286 90 0.207 0.269 100 0.196 0.256 n α=0.05 α=0.01 The regression equation is y= ___________+___________x. (Round to five decimal places as needed.) The best predicted circumference for a diameter of 1.2cm is _________cm. (Round to one decimal place as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Section 10.2
Question #12
Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marblewith a diameter of 1.2 cm. How does the result compare to the actual circumference of 3.8 cm? Use a significance level of 0.05.
|
|
Baseball
|
Basketball
|
Golf
|
Soccer
|
Tennis
|
Ping-Pong
|
Volleyball
|
|
|---|---|---|---|---|---|---|---|---|
|
Diameter
|
7.5
|
24.3
|
4.2
|
21.7
|
6.9
|
4.1
|
20.7
|
|
|
Circumference
|
23.6
|
76.3
|
13.2
|
68.2
|
21.7
|
12.9
|
65.0
|
|
View the critical values of the Pearson correlation coefficient r.
Critical values of the pearson correlation coefficient r
|
n
|
α=0.05
|
α=0.01
|
NOTE: To test H0: ρ=0 against H1: ρ≠0, reject H0 if the absolute value of r is greater than the critical value in the table. |
|---|---|---|---|
|
4
|
0.950
|
0.990
|
|
|
5
|
0.878
|
0.959
|
|
|
6
|
0.811
|
0.917
|
|
|
7
|
0.754
|
0.875
|
|
|
8
|
0.707
|
0.834
|
|
|
9
|
0.666
|
0.798
|
|
|
10
|
0.632
|
0.765
|
|
|
11
|
0.602
|
0.735
|
|
|
12
|
0.576
|
0.708
|
|
|
13
|
0.553
|
0.684
|
|
|
14
|
0.532
|
0.661
|
|
|
15
|
0.514
|
0.641
|
|
|
16
|
0.497
|
0.623
|
|
|
17
|
0.482
|
0.606
|
|
|
18
|
0.468
|
0.590
|
|
|
19
|
0.456
|
0.575
|
|
|
20
|
0.444
|
0.561
|
|
|
25
|
0.396
|
0.505
|
|
|
30
|
0.361
|
0.463
|
|
|
35
|
0.335
|
0.430
|
|
|
40
|
0.312
|
0.402
|
|
|
45
|
0.294
|
0.378
|
|
|
50
|
0.279
|
0.361
|
|
|
60
|
0.254
|
0.330
|
|
|
70
|
0.236
|
0.305
|
|
|
80
|
0.220
|
0.286
|
|
|
90
|
0.207
|
0.269
|
|
|
100
|
0.196
|
0.256
|
|
|
n
|
α=0.05
|
α=0.01
|
The regression equation is y= ___________+___________x.
(Round to five decimal places as needed.)
The best predicted circumference for a diameter of 1.2cm is _________cm.
(Round to one decimal place as needed.)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 5 images
Recommended textbooks for you
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman