Find the position vector for a particle with acceleration, initial velocity, and initial position given below. ā(t) = (3t, 6 sin(t), cos(5t)) v(0) = ( − 3, — 1,0) - 7(0) = (0, – 5,0) - r(t) =

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter5: Trigonometric Functions: Right Triangle Approach
Section5.1: Angle Measure
Problem 4E: Object A is travelling along a circle of radius 2, and Object B is travelling along a circle of...
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### Problem Statement:

Find the position vector for a particle with acceleration, initial velocity, and initial position given below.

### Given Data:

**Acceleration:**
\[
\vec{a}(t) = \langle 3t, 6 \sin(t), \cos(5t) \rangle
\]

**Initial Velocity:**
\[
\vec{v}(0) = \langle -3, -1, 0 \rangle
\]

**Initial Position:**
\[
\vec{r}(0) = \langle 0, -5, 0 \rangle
\]

### Required Solution:

**Position Vector:**
\[
\vec{r}(t) = \left\{\begin{array}{c}
\ \text{[enter x-component here]}\ , \\
\ \text{[enter y-component here]}\ , \\
\ \text{[enter z-component here]}\ 
\end{array}\right\}
\]

### Explanation:

You need to determine the position vector \(\vec{r}(t)\) by integrating the given acceleration vector \(\vec{a}(t)\) to find the velocity vector \(\vec{v}(t)\), and then integrating \(\vec{v}(t)\) to find the position vector \(\vec{r}(t)\).
Transcribed Image Text:### Problem Statement: Find the position vector for a particle with acceleration, initial velocity, and initial position given below. ### Given Data: **Acceleration:** \[ \vec{a}(t) = \langle 3t, 6 \sin(t), \cos(5t) \rangle \] **Initial Velocity:** \[ \vec{v}(0) = \langle -3, -1, 0 \rangle \] **Initial Position:** \[ \vec{r}(0) = \langle 0, -5, 0 \rangle \] ### Required Solution: **Position Vector:** \[ \vec{r}(t) = \left\{\begin{array}{c} \ \text{[enter x-component here]}\ , \\ \ \text{[enter y-component here]}\ , \\ \ \text{[enter z-component here]}\ \end{array}\right\} \] ### Explanation: You need to determine the position vector \(\vec{r}(t)\) by integrating the given acceleration vector \(\vec{a}(t)\) to find the velocity vector \(\vec{v}(t)\), and then integrating \(\vec{v}(t)\) to find the position vector \(\vec{r}(t)\).
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1/2-1/25cos(5t) is wring could you please check it again? thank you!

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

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