Find the normal stress value on the new x-axis obtained by turning 53 ° clockwise of the stressed element in the figure. Formül;TL60 MPaTmaks =1-0,630b/a)45 MPaCab³G' 5>5 için c = cz =T• Oy =2tAM2(1zy.2- ly-y) + M,(1,.z – Izy.y)VQМy= 1ItI.ly – Izy?100 MPa100MPAOx + Oy Ix - Oycos20 + Txysin20 , Jort =22TxyOx + đy, tan28, -Ox- OyOx + OyTy = -sin20 + Tyycos20 , ơmaks.min =2+ T,45 MPa60 MPaTmaks =+ TyŞekilde gerilme durumu verilen elemanın, saat yönünde 53° dönmesiyle elde edilen yeni xekseninin üzerindeki normal gerilme değerini bulunuz.6,85 MPa-31,23 MPa31,23 MPaHiçbiri-6,85 MPa

Sigma 1 = 100 Mpa Sigma 2 = 60 Mpa shear stress = 45 Mpa

Answered: Find the normal stress value on the new…

Find the normal stress value on the new x-axis obtained by turning 53 ° clockwise of the stressed element in the figure.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.

Question

Find the normal stress value on the new x-axis obtained by turning 53 ° clockwise of the stressed element in the figure.

Formül;
TL
60 MPa
Tmaks =
1-0,630b/a)
45 MPa
Cab³G' 5>5 için c = cz =
T
• Oy =
2tA
M2(1zy.2- ly-y) + M,(1,.z – Izy.y)
VQ
Мy
= 1
It
I.ly – Izy?
100 MPa
100MPA
Ox + Oy Ix - Oy
cos20 + Txysin20 , Jort =
2
2Txy
Ox + đy, tan28, -
Ox- Oy
Ox + Oy
Ty = -
sin20 + Tyycos20 , ơmaks.min =
2
+ T,
45 MPa
60 MPa
Tmaks =
+ Ty
Şekilde gerilme durumu verilen elemanın, saat yönünde 53° dönmesiyle elde edilen yeni x
ekseninin üzerindeki normal gerilme değerini bulunuz.
6,85 MPa
-31,23 MPa
31,23 MPa
Hiçbiri
-6,85 MPa

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