Find the most economical wide flange section for an A992 steel beam (E = 29 x 10³ ksi) which spans 30 ft. having point loads of 9 k dead load and 18 k live load at 10 ft spacings across the span with lateral bracing only at the loading points using LRFD. Assume the total load deflection limit is L/240. (See Table 3-10 provided.)

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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lat 08
Fy= 50 ksi
Co = 1
peunitnoo) O Table 3-10 (continued)
egs W-Shapes
Fy = 50 ksi
Cp = 1
Table 3-10 (continued)
W-Shapes
kip-ft
kip-ft
Available Moment vs. Unbraced Length
kip-ft
ASD
kip-ft
LRFD
Available Moment vs. Unbraced Length
ASD
LRFD
200
300
300
W10x100
450
wi2x79-
196
294
W14x48
290
435
W12x53-
LW14x68_
W10x88|
192
288
280
420
W18x55
W21x50-
188
282
270
405
W12x72
W10x60
W21x48
W16x57
184
276
260
390
w16x40)
W14x61
W18x50
180
270
W12x50–
250
375
W12172
W10x77
176
264
240
360
tw21x44"
W8x67_
wi2x65
W14x43
172
258
230
345
168
252
220
330
tw10x54 |
W14x53
W12x58
W18x35
W10x68
164
246
210
315
W16x45
W12x45
160
240
200
300
W16x36
4
6
8
10
12
14
16
18
20
2
4
6.
10
12
14
16
18
Unbraced Length (0.5-ft increments)
Unbraced Length (0.5-ft increments)
W14x82
W12
/12x87
W12x
W14x68
W12x65
W24x6
W14x61
W14x53 /
4x62 w10x68-
W12x58
W24x62
Available Moment, M„IS2o (2 kip-ft increments) and oOM, (3 kip-ft increments)
„W16x57|
| W21x48-
W18x50
W18x55
w2ix57
-tw16x57
W18Y55
W21x50
W21x50
Lw12«53..
W18x50
w21x44
W16x50
W24x55**-
W18x46
W16x45 L . -- -*
W14x48
W21x44
WI4x48
wi6x45
W18x46
w16×45
W18x40
W12x50
w14x43
|W16x40
W18x40
Available Moment, M„IS2o (1 kip-ft increments) and oM, (1.5 kip-ft increments)
Transcribed Image Text:lat 08 Fy= 50 ksi Co = 1 peunitnoo) O Table 3-10 (continued) egs W-Shapes Fy = 50 ksi Cp = 1 Table 3-10 (continued) W-Shapes kip-ft kip-ft Available Moment vs. Unbraced Length kip-ft ASD kip-ft LRFD Available Moment vs. Unbraced Length ASD LRFD 200 300 300 W10x100 450 wi2x79- 196 294 W14x48 290 435 W12x53- LW14x68_ W10x88| 192 288 280 420 W18x55 W21x50- 188 282 270 405 W12x72 W10x60 W21x48 W16x57 184 276 260 390 w16x40) W14x61 W18x50 180 270 W12x50– 250 375 W12172 W10x77 176 264 240 360 tw21x44" W8x67_ wi2x65 W14x43 172 258 230 345 168 252 220 330 tw10x54 | W14x53 W12x58 W18x35 W10x68 164 246 210 315 W16x45 W12x45 160 240 200 300 W16x36 4 6 8 10 12 14 16 18 20 2 4 6. 10 12 14 16 18 Unbraced Length (0.5-ft increments) Unbraced Length (0.5-ft increments) W14x82 W12 /12x87 W12x W14x68 W12x65 W24x6 W14x61 W14x53 / 4x62 w10x68- W12x58 W24x62 Available Moment, M„IS2o (2 kip-ft increments) and oOM, (3 kip-ft increments) „W16x57| | W21x48- W18x50 W18x55 w2ix57 -tw16x57 W18Y55 W21x50 W21x50 Lw12«53.. W18x50 w21x44 W16x50 W24x55**- W18x46 W16x45 L . -- -* W14x48 W21x44 WI4x48 wi6x45 W18x46 w16×45 W18x40 W12x50 w14x43 |W16x40 W18x40 Available Moment, M„IS2o (1 kip-ft increments) and oM, (1.5 kip-ft increments)
3) Find the most economical wide flange section for an A992 steel beam (E = 29 x 10³ ksi)
which spans 30 ft. having point loads of 9 k dead load and 18 k live load at 10 ft spacings
across the span with lateral bracing only at the loading points using LRFD. Assume the total
load deflection limit is L/240. (See Table 3-10 provided.)
Transcribed Image Text:3) Find the most economical wide flange section for an A992 steel beam (E = 29 x 10³ ksi) which spans 30 ft. having point loads of 9 k dead load and 18 k live load at 10 ft spacings across the span with lateral bracing only at the loading points using LRFD. Assume the total load deflection limit is L/240. (See Table 3-10 provided.)
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