Find the minimum sample size n needed to estimate u for the given values of c, o, and E. c= 0.98, o = 9.6, and E= 2

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**Determining Sample Size for Estimating Population Mean (μ)**

To find the minimum sample size \( n \) required to estimate the population mean \( \mu \) for the given values of confidence level ( \( c \) ), population standard deviation ( \( \sigma \) ), and margin of error ( \( E \) ), use the following information:

**Given:**
- Confidence level, \( c = 0.98 \)
- Population standard deviation, \( \sigma = 9.6 \)
- Margin of error, \( E = 2 \)

**Instruction:**
Assume that a preliminary sample has at least 30 members.

**Formula:**
\( n = \left( \frac{ z \sigma }{ E } \right)^2 \)

To find the \( z \)-score corresponding to the confidence level, and then use it to compute the sample size:

1. **Identify \( z \)-score:**
   For a \( 98\% \) confidence level, the corresponding \( z \)-score can be found using statistical tables or computational tools.

2. **Calculate sample size (\( n \)):**
   Substitute the given values into the formula and round up to the nearest whole number.

**Note:** Round up to the nearest whole number to ensure the sample size is adequate for the desired level of confidence.

\[
n = \left( \frac{ z \sigma }{ E } \right)^2
\]

(Here, the actual calculation steps and the \( z \)-score would typically be provided for instructional purposes.)

**Result:**
\[ n = \text{(Insert the computed value here)} \]

This calculation helps ensure that the sample size is sufficient to estimate the population mean with the specified level of confidence and margin of error.
Transcribed Image Text:**Determining Sample Size for Estimating Population Mean (μ)** To find the minimum sample size \( n \) required to estimate the population mean \( \mu \) for the given values of confidence level ( \( c \) ), population standard deviation ( \( \sigma \) ), and margin of error ( \( E \) ), use the following information: **Given:** - Confidence level, \( c = 0.98 \) - Population standard deviation, \( \sigma = 9.6 \) - Margin of error, \( E = 2 \) **Instruction:** Assume that a preliminary sample has at least 30 members. **Formula:** \( n = \left( \frac{ z \sigma }{ E } \right)^2 \) To find the \( z \)-score corresponding to the confidence level, and then use it to compute the sample size: 1. **Identify \( z \)-score:** For a \( 98\% \) confidence level, the corresponding \( z \)-score can be found using statistical tables or computational tools. 2. **Calculate sample size (\( n \)):** Substitute the given values into the formula and round up to the nearest whole number. **Note:** Round up to the nearest whole number to ensure the sample size is adequate for the desired level of confidence. \[ n = \left( \frac{ z \sigma }{ E } \right)^2 \] (Here, the actual calculation steps and the \( z \)-score would typically be provided for instructional purposes.) **Result:** \[ n = \text{(Insert the computed value here)} \] This calculation helps ensure that the sample size is sufficient to estimate the population mean with the specified level of confidence and margin of error.
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